1-Amaliy ish. Bitta tik stvol orqali yo`naltirish-bog`lash uchburchagining parametrlarini hisoblash. Ishdan maqsad

Direksion va rumb burchaklari orasidagi munosabat

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1-amaliy ish

Orttirmalar ishorasi jadvali

Direksion va rumb burchaklari orasidagi munosabat.

Choraklar	Direksion burchak qiymati	Rumb nomi	Direksion burchak orqali rumbni hisoblash	Rumb orqali direksion burchakni hisoblash
I II III IV	0<₁<90 90<₂<180 180<₃<270 270<₄<360	SHSH_Q JSH_Q JG` SHG`	r₁=₁ r₂=180-₂ r₃=₃-180 r₄=360-₄	₁=r₁ ₂=180-r₂ ₃=180+r₃ ₄=360-r₄

5.1 Birinchi yo`l bo`yicha tomonlar rumb burchaklarini hisoblaymiz.

r_DC = 180 - _DC = 180 - 1031313 = 764647 (JSH_q);
r_CA = 180 - _CA – 180 - 990323 = 805637 (JSH_q);
r_AB = 360 - _AB = 360 - 2750718 = 845242 (SHG`);
r_B__C_ = _B__C_ - 180 = 2691109 – 180 = 891109 (SHG`);
r_C__D_ = 360 - _C__D_ = 360 - 2894548 = 701412 (SHG`).
5.2 Ikkinchi yo`l bo`yicha tomonlar rumb burchaklarini hisoblaymiz.
r_DC = 180 - _DC = 180 - 1031313 = 764647 (JSH_q);
r_CB = 180 - _CB = 180 - 1014013 = 781947 (JSH_q);
r_BA = 180 - _VA = 180 - 950718 = 845242 (JSH_q);
r_A__C_ = 360 - _A__C_ = 360 - 2713906 = 882054 (SHG`);
r_C__D_ = 360 - _C__D_ = 360 - 2894548 = 701412 (SHG`).
6. Birinchi va ikkinchi yo`llar bo`yicha koordinatalar orttirmalarini quyidagi formulalardan foydalanib hisoblaymiz;
x_i=d_icosr_i,
y_i=d_isinr_i. (1.5)
bu yerda: d_i – tomon uzunliklari; r_i – tomonlarning rumb burchaklari.
Topilgan koordinatalar orttirmalari oldiga tegishli rumb burchaklar asosida ishoralari (1.2-jadvalda keltirilgan) qo`yiladi.
1.2-j a d v a l
Orttirmalar ishorasi jadvali

Choraklar	Rumblar nomi	Orttirmalar ishorasi
		X	Y
I II III IV	SHSH_q JSH_q JG` SHG`	+ — — +	+ + — —

6.1 Birinchi yo`l bo`yicha koordinatalar orttirmalari x, y larni hisoblaymiz.

x_DC = DC cos_DC = 8,260cos1031313 = -1,889 m;
x_CA = b cos_CA = 10,198cos990323 = -1,605 m;
x_AB = c cos_AB = 4,078cos2750718 = 0,364 m;
x_B__C_ = a cos_B__C_ = 5,737cos2691109 = -0,081 m;
x_C__D_ = CD cos_C__D_ = 15,662cos2894548 = 5,296 m.

y_DC = DC sin_DC = 8,260sin1031313 = 8,041 m;

y_CA = b sin_CA = 10,198sin990323 = 10,071 m;
y_AB = c sin_AB = 4,078sin2750718 = -4,062 m;
y_B__C_ = a sin_B__C_ = 5,737sin2691109 = -5,736 m;
y_C__D_ = CD sin_C__D_ = 15,662sin2894548 = -14,739 m.
6.2 Ikkinchi yo`l bo`yicha koordinatalar orttirmalari x, y larni hisoblaymiz.
x_DC = DC cos_DC = 8,260cos1031313 = -1,889 m;
x_CB = a cos_CB = 6,136cos1014013 = -1,241 m;
x_BA = c cos_BA = 4,078cos950718 = -0,364 m;
x_A__C_ = b cos_A__C_ = 9,802cos2713906 = 0,283 m;
x_C__D_ = CD cos_C__D_ = 15,662cos2894548 = 5,296 m.
y_DC = DC sin_DC = 8,260sin1031313 = 8,041 m;
y_CB = a sin_CV = 6,136sin1014013 = 6,009 m;
y_B_A = c sin_BA = 4,078sin950718 = 4,062 m;
y_A__C_ = b sin_A__C_ = 9,802sin2713906 = -9,798 m;
y_C__D_ = CD sin_C__D_ = 15,662sin2894548 = -14,739 m.
7. Birinchi va ikkinchi yo`llar bo`yicha nuqtalar koordinatalari x, y larni quyidagi formulalardan foydalanib hisoblaymiz;
x_D = 1000,000 + 10,010  n.
y_D = 2000,000 + 10,010  n.
x_i=x_i-1  x_i-1,
y_i=y_i-1  y_i-1. (1.6)
7.1 Birinchi yo`l bo`yicha nuqtalar kordinatalari x, y larni hisoblaymiz.
x_C = x_D + x_DC = 1130,000 - 1,889 = 1128,111 m;
x_A(A_₎ = x_C + x_C_A = 1128,111 - 1,605 = 1126,506 m;
x_B_(B_₎ = x_A(A_₎ + x_A_B= 1126,506 + 0,364 = 1126,870 m;
x_C_ = x_B(B_₎ + x_B__C_ = 1126,870 - 0,081 = 1126,789 m;
x_D_ = x_C_ + x_C__D_ = 1126,789 + 5,296 = 1132,085 m.

y_C = y_D + y_DC = 2130,000 + 8,041 = 2138,041 m;
y_A(A_₎ =y_C + y_C_A = 2138,041 + 10,071 = 2148,112 m;
y_B_(B_₎ = y_A(A_₎ + y_A_B = 2148,112 - 4,062 = 2144,050 m;
y_C_ = y_B_(B_₎ + y_B__C_ = 2144,050 - 5,736 = 2138,314 m;
y_D_ = y_C_ + y_C__D_ = 2138,314 - 14,739 = 2123,575 m.
7.2 Ikkinchi yo`l bo`yicha nuqtalar koordinatalari x, y larini hisoblaymiz.
x_C = x_D + x_DC = 1130,000 - 1,889 = 1128,111 m;
x_B(B_₎ = x_C + x_CB = 1128,111 - 1,241 = 1126,870 m;
x_A(A_₎ = x_B_(B_₎ + x_BA = 1126,870 - 0,364 = 1126,506 m;
x_C_ = x_A(A_₎ + x_A__C_ = 1126,506 + 0,283 = 1126,789 m;
x_D_ = x_C_ + x_C__D_ = 1126,789 + 5,296 = 1132,085 m.
y_C = y_D + y_DC = 2130,000 + 8,041 = 2138,041 m;
y_B_(B_₎ = y_C + y_CB = 2138,041 + 6,009 = 2144,050 m;
y_A(A_₎ = y_B_(B_₎ + y_B_A = 2144,050 + 4,062 = 2148,112 m;
y_C_ = y_A(A_₎ + y_A__C_ = 2148,112 - 9,798 = 2138,314 m;
y_D_ = y_C_ + y_C__D_ = 2138,314 - 14,739 = 2123,575 m.
8. O`lchash va kameral sharoitda hisoblangan natijalarni yo`naltirish – bog`lash tasviri punktlari koordinatalarini hisoblash jadvaliga yozamiz. Natijalarni jadvalga yozish 1.3 – va 1.4 – jadvallarda ko`rsatilgan.
9. Topilgan nuqtalar koordinatalari yordamida yo`naltirish – bog`lash tasviri planini millimetrli qog`ozda chizamiz. Yo`naltirish – bog`lash tasviri plani 1.1-rasmda keltirilgan.

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