1. Hozirgi zamon laboratoriya usullari bilan idishdagi havo so‘rib olinib u juda siyraklashtirilgan (p=10-11mm sim ust.) bo‘lsa 100C haroratda idishning har 1sm3 hajmda qancha molekula bo‘ladi. Berilishi

1 .Hozirgi zamon laboratoriya usullari bilan idishdagi havo so‘rib olinib u juda siyraklashtirilgan (p=10-11mm sim. ust.) bo‘lsa 100C haroratda idishning har 1sm3 hajmda qancha molekula bo‘ladi.

Berilishi:	Formula:	Yechish:
P=10^-11 mm sim.ust T=10^0C=283K V=1 sm^3 N=?	PV=VRT V= PV/RT N= VNA	V=10^-11∙133,3∙10^-6/8,31∙283= 0,057∙10^-17 N=0,057∙10^-17∙6,02∙10^23 =3,4∙10^5 ta

2. Shisha idishda yaxshi vakuum olish uchun adsorbsiyalangan gazni chiqarishda idish devorlarini qizdirish zarurdir. Agar adsorbsiyalangan gaz molekulalari idish devoridan idish ichiga o‘tsa, u holda r=10 sm raduysli sferik idishdagi bosimning qanchaga ortishi hisoblansin. Adsorbsiya qatlamini molekular qatlam deb, molekulaning ko‘ndalang kesimini esa 10^-15 sm² deb olinsin. Harorat t=3000C.

Berilishi:	Formula:	Yechish:
r=10sm S=10^-15sm^2 T=300^0C=573K P=? N/m^3	P=NKT/V N=S1/S P=3kT/Sr	P=3∙1,38∙10^-23∙573/10^-15∙10^-4∙0,1 =2,4N/m^3

3. Agar yodning dissotsiatsya darajasi 50% bo‘lsa, uning 1g bug‘ida qancha zarracha bo‘ladi. Yod J₂ ning bir kilomol massasi 254 kg/kmol ga teng.

Berilishi:	Formula:	Yechish:
a=50% m=1g μ =254 kg/kmol N=?	N=NA(2 a m/ μ+(1- a) m/ μ)	N= ^23(2 /254+(1-0,5) 1/254= 35,6 ^20=3,56 ^21 N=3,56 ^21ta

4. Yarmisi dissotsiatsiyalangan 16g kislorodda qancha zarracha bo‘ladi?

Berilishi:	Formula:		Yechish:
m=16g mmol=8g matom=8g μ mole=32g/mol μ atom=16g/mol N=?	N=( mmol/ μ mole+ matom/ μ atom) A	N=(8/32+8/16) ^23 =4,515 ^23

5. Idishda 10^-10 kilomol kislorod va 10^-6 g azot bor. Aralashmaning harorati 100⁰ Cga teng. Bunda idishdagi bosim 10^-3 mm sim.ust.ga teng. 1)idishning hajmi, 2)kislorod va azotning portsial bosimi, 3) idishning har 1sm³ hajmidagi molekulyar soni topilsin.

Berilishi:	Formula:	Yechish:
v1=10^-7mol m2=10^-9kg T=100^0C=373K μ1=32g/mol μ2=28g/mol V0=1sm^3 V=? P1=? P2=?	V=( v1+ v2)RT/P P1=v1RT/V P2=P-P1	V= =3,2 ^-3m^3 P1= =96 mm.sim.ust P2=(133-96) =37 Pa= 2,7 mm.sim.ust

6. Havoni bir kilomolining massasi μ=29 kg/kilomolga teng bo‘lgan bir jinsli gaz deb hisoblab, 170C haroratda havo molekulalarining o‘rtacha kvadratik tezligi topilsin.

Berilishi:	Formula:	Yechish:
μ=29∙10^-3 kg/mol T=170^0C=290K v=?		v= =500m/s

7. Bir xil haroratdagi geliy va azot molekulalari o‘rtacha kvadratik tezliklarning nisbati topilsin.

Berilishi:	Formula:	Yechish:
T1=T2 M1=4 g/mol M2=28 g/mol v1/v2=?	v	v1/v2= = = = =2,65

8. Atom bombasi portlash paytida harorat taxminan 10⁶ C gradusgacha ko‘tariladi. Bunday haroratda hamma molekulalarni atomlarga dissotsiatsiyalangan, atomlarni esa ionlashgan hisoblab, vodorod ionning o‘rtacha kvadratik tezligi topilsin.

Berilishi:	Formula:	Yechish:
T=10^6C M=1g/mol v=?	v	v= =5∙10^5m/s

9. Agar 200 mm sim.ust.bosimida vodorod molekulasining o‘rtacha kvadratik tezligi 2400 m/sek ga teng bo‘lsa, bu sharoitda 1sm³ hajmdagi vodorod molekulalarning soni topilsin.

Berilishi:	Formula:	Yechish:
P=200 mm sim.ust v=2400 m/s V=1sm^3=10^-6 m^3 M=2g/mol N=?	V= PV/RT=3PV/ v^2M N=NA V	V=3∙26666∙10^-6/(576∙10^4∙2∙10^-3)= 69,44∙10^-7 N=69,44∙10^-7∙6,02∙10^23=4,18∙10^18ta N=4,18∙10^18ta

10. Biror gazning zichligi 6∙10^-2 kg/m3 ga, molekulalarning o‘rtacha kvadratik tezligi esa 500 m/sek ga teng. Gazning idish devoriga ta‘sir qilgan bosimi topilsin

Berilishi:	Formula:	Yechish:
p=6∙10^-2kg/m^3 v=500 m/s P=?		P=10^-2∙6∙25∙10^4/3=5000 Pa P=5kPa