1 Ma’ruza Reja


Download 389.27 Kb.
bet8/8
Sana28.02.2023
Hajmi389.27 Kb.
#1237443
1   2   3   4   5   6   7   8
Bog'liq
1-Маъруза

1.11 - rasm. Davriy bo’lmagan aperiodik tebranish
Qaytarish uchun nazorat savollari

  1. Qanday tebranishlar garmonik tebranishlar deyiladi?

  2. Garmonik tebranishning amplitudasi deb nimaga aytiladi?

  3. Garmonik tebranishning fazasi deb nimaga aytiladi?

  4. Garmonik tebranishning davri deb nimaga aytiladi?

  5. Garmonik tebranishning chastotasi deb nimaga aytiladi?

  6. Garmonik tebranishning siklik chastotasi deb nimaga aytiladi?

  7. Garmonik tebranishning differensial tenglamasini yozib bering.

  8. Garmonik tebranayotgan jismlarning to’la mexanik energiyasi qanday?

  9. Prujinali mayatnikning tebranish davri qanday topiladi?

  10. Matematik mayatnikning tebranish davri qanday topiladi?

  11. Fizik mayatnikning tebranish davri qanday topiladi?

  12. Tebranishlarni qo’shish qanday bajariladi

  13. Erkin mexanik tebranishlar tenglamasini yozing.

  1. Erkin so’nuvchi tebranishlarning differensial tenglamasini yozing.

  2. So’nish koeffisiyenti nima?

  3. So’nish dekrementi nima?

  4. So’nishning logarifmik dekrementi nima?

  5. Davriy bo’lmagan aperiodik tebranish qanday hosil bo’ladi?



TEST.
1. Berilgan tenglamalar orasidan matematik mayatnikning tebranish davri ifodasini aniqlang.
A) B)
C) D)
2. Berilgan tenglamalar orasidan prujinali mayatnikning tebranish davri ifodasini aniqlang.
A) B)
C) D)
3. Matematik mayatnik uzunligi qanday bo‘lganda uning tebranish davri 6,28 s ga teng bo‘ladi (m)? g=10 m/s2
A) 1,6 B) 6.28 C) 3,14 D) 10
4. Ipining uzunligi l bo‘lgan matematik mayatnikning tebranish davri T ga teng. Agar ipning 1/2 qism uzunligini kesib tashlab, qolgan qismiga yana o‘sha yuk osilsa, tebranish davri qanday bo‘ladi?
A) T/4 B) C) T / D)
5. Matematik mayatnikning tebranish chastotasi qanday formula bilan ifodalanishini ko‘rsating.
A) B)
C) = D) =

6. Keltirilgan kattaliklardan qay biri tebranuvchi jismning xususiy xossasini tavsiflaydi? To‘g‘ri javobni tanlang.


A) tebranishlar amplitudasi
B) tebranishlarning boshlang‘ich fazasi
C) tebranishlar fazasi
D) tebranishlar chastotasi
7. Matematik mayatnik 1 minutda 180 marta tebranadi. Tebranish chastotasini aniqlang (Hz).
A) 6 B) 2 C) 3 D) 12
8. Tebranma harakatda siklik chastota nima?
A) bitta tebranish uchun ketgan vaqt
B) 1 sekunddagi tebranishlar soni
C)  sekunddagi tebranishlar soni
D) 2 sekunddagi tebranishlar soni

9. Matematik mayatnikning bir davri davomida uning potensial energiyasi necha marta kinetik energiyaga aylanadi?


A) 3 marta B) 2 marta C) 4 marta D) 1 marta

10. Birinchi matematik mayatnikning tebranish davri 8 s, ikkinchisiniki 6 s. Ularning uzunliklari yig‘indisiga teng uzunlikdagi matematik mayatnikning tebranish davrini hisoblang (s).


A) 10 B) 12 C) 14 D) 5
11. Matematik mayatnikning yerdagi tebra­nish davri T ga teng bo‘lsa, erkin tus­hish tezlanishi yerdagidan n marta katta bo‘lgan planetadagi tebranish davri nimaga teng?
A) n2T B) nT C) T D)
12. Yerda tebranish chastotasi 0,5 Hz bo‘lgan matematik mayatnik Oyga olib chiqilsa, u qanday chastotada tebranadi (Hz)? Oyda erkin tushish tezlanishi yerdagidan 6 marta kichik.
A) 0,3 B) 0,2 C) 1,2 D) 0,5

13. Oyga yerdan olib chiqilgan matematik mayatnikning tebranish davri yerdagidek bo‘lishi uchun uning uzunligini qanday o‘zgartirish kerak. Oyda erkin tushish tezlanishi yerdagidan 6 marta kichik.


A) o‘zgartirish kerak emas B) 6 marta orttirish kerak
C) 36 marta qisqartirish kerak D) 6 marta qisqartirish kerak
14. Qanday sharoitda matematik mayatnikning tebranish davri cheksiz katta bo‘ladi?
A) bunday bo‘lishi mumkin emas
B) ekvatorda C) qutbda D) vaznsizlikda

15.Fizik mayatnikning tebranish davri ifodasini toping.


A) B) C) D)
16. Kichik jism l uzunlikdagi ipga osilgan holda A amplituda bilan tebranmokda. Jismning maksimal tezligini toping.
A) B)
C) D)
17. m massali sharcha l uzunlikdagi ipga osilgan holda A amplituda bilan tebranmoqda. Sharchaning maksimal kinetik energiyasini toping.
A) B) C) D)

18. So’nish koeffisiyentini ifodasini ko’rsating


A. B. C. D.

19. Bikrligi 625 N/m bo‘lgan prujinaga osilganda 4 s da 5 marta bo‘ylama tebranadigan yukning massasini hisoblang.


A) 10 kg B) 2 kg C) 4 kg D) 8 kg

20. Erkin so’nuvchi tebranishlarning differensial tenglamasi ifodasini toping


A. B.


C. D.
Download 389.27 Kb.

Do'stlaringiz bilan baham:
1   2   3   4   5   6   7   8




Ma'lumotlar bazasi mualliflik huquqi bilan himoyalangan ©fayllar.org 2024
ma'muriyatiga murojaat qiling