1 topshiriq. Berilgan savollarga yozma tarzda javob tayyorlang


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109671 Вариант 28 (1)MATEM

4 – topshiriq: Nomanfiy butun sonlarni qo`shish


, bu yerda va .
Masalan: to`plamlarni olamiz. Ularni birlashtiramiz. sanash yo`li bilan ekanligini aniqlaymiz. . Demak, 5+2=7.
To’plam nazariyasiga ko’ra ta’rifiga asoslanib, 9+5, 5+3, 8+5 ni hisoblash yo’lini ko’rsating.
To’plamnazariyasigako’rata’rifigaasoslanib, 7+5, 4+6, 2+3, 5+4 ni hisoblash yo’lini ko’rsating.
To’plam nazariyasiga ko’ra ta’rifiga asoslanib, 9+0, 0+3, 0+0, 8+2 ni hisoblash yo’lini ko’rsating.



  1. 27+39+13+11=90

  2. 38+94+12+16=160

  3. 49+29+87+31+51+13=260

  4. 18+39+27+12+23=119

O‘rin almashtirish va gruppalash qonunlaridan foydalanib, quyidagi misollarni eng qulay yo‘l bilan yeching:

  1. 2608+529+392+271=2000+608+500+29+300+92+200+71=3800

  2. 1016+704+250+884+296=1000+16+704+200+50+800+84+200+96=3150

  3. 10556+8074+ 9444+926+1000=30000

  4. 1720+863+280+137=3000

Quyidagi yig‘indilarini ikki usul bilan toping:



  1. 4098+(1765+7908)=13771

  2. 7509+(12078+9067)=28654

  3. 15728+(4987+3751+7399)=31865

  4. 10087+(3445+5684+7889)=27105



5 – topshiriq:
Masalani yeching

  1. Valida 18 marka bor. Umidada Validan 6 marka kam, Sevarada esa Vali bilan Umidaning markalaridan 12 ta marka kam. Sevarada qancha marka bor? SEVARADA 18 TA MARKA BOR.

  2. Teng yonli uchburchakning asosi yon tomonidan 7 sm ortiq. Agar uchburchakning perimetri 43 sm bo‘lsa, uning yon tomoni toping. YON TOMONI 12 GA TENG

  3. Kinoteatrning bir kassasida ikkinchisiga qaraganda 86 ortiq bilet sotildi.Agar xammasi bulib 792 ta bilet sotilgan bo‘lsa, har bir kassada nechta bilet sotilgan?

JAVOB; 353 TA BILET

  1. Uchburchakning perimetri 24 sm. Uchburchakning ikki tomoni bir – biriga teng bo‘lib, ularning har biri uchinchi tomonidan 3 sm ortiq. Uchburchakning tomonlari necha santimetrdan? JAVOB; 1VA 2 TOMONLARI 9SMDAN 3 TOMONI 6SM




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