2. Dastgoh xaqida umumiy ma’lumot

Dastgoh xaqida umumiy ma’lumot.
6П80Г Universal frezalash dastgohi

3. Asosiy kinematik parametrlarni aniqlash
6П80Г- Gorizontal frezalash dasgoxi asosida tezliklar qutisini loyixalash.
1. SHipindelning eng kichik aylanishlar soni – n_min=32 ayl/daq
2. SHipindelning eng katta aylanishlar soni – n_max=1500 ayl/daq
3. Tezliklar soni va formulasi – Z=16=2*4*2
4. Eng kata ishlov berish o‘lchamlari – B=70 mm, L=120 mm, h=5 mm.
5. Ishlov beriladigon material - Сталь 35 Ϭ_b =530 MPA

3.1 Dastgoh shpindelining n dan n_max gacha bo’lgan oraliqdagi aylanish chastotasi qatori hisoblanadi.
n_min=n₁;
n₂=n₁ ;
n₃=n₂ =n₁ =n₁ ²;
n₃=n₂ =n₁ =n₁ ²………………………….
n_max=n_z=n₁ ^z-1}
ketma ketlik bajarilishi kerak bo’lib u geometrik progressiyani tashkil qiladi.
Bu yerda geometrik progressiya maxraji bo’lib
ga teng.
Z=16=4*4 ekanligidan
Standardga yaqin qiymat =1.26 deb qabul qilamiz
Standart qiymat qabul qilamiz.

n_min= 37 ayl/min

n₂=37*1.26= 46 ayl/min
n₃=37*1.26²= 58 ayl/min
n₄=37*1.26³= 74 ayl/min
n₅=37*1.26⁴= 93 ayl/min
n₆=37*1.26⁵= 117 ayl/min
n₇=37*1.26⁶= 148 ayl/min
n₈=37*1.26⁷= 186 ayl/min
n₉=37*1.26⁸= 235 ayl/min
n₁₀=37*1.26⁹= 296 ayl/min
n₁₁=37*1.26¹⁰= 373 ayl/min
n₁₂=37*1.26¹¹= 470 ayl/min
n₁₃=37*1.26¹²= 592 ayl/min
n₁₄=37*1.26¹³= 746 ayl/min
n₁₅=37*1.26¹⁴= 940 ayl/min
n₁₆=37*1.26¹⁵= 1185 ayl/min

1- Hol uchun
III I II	I = X1^0= 1 II = X1= 4 III = X1= 8

2- Hol uchun
II I III	I = X1^0= 1 II = X1= 4 III = X1= 8

2-Hol uchun aylanishlar chastatasi grafigi quramiz.

4. Tezliklar uzatmasi qutisining kinematik sxemasini va struktura grafigini qurish.
=1.26
= ² =1.26 ² =1.58
^-6= 1.26^-6 =
¹ = 1.26¹ = 1.26
⁰=1.26⁰ = 1
= ^-1 = 1.26^-1 =
^-2 = 1.26^-2 =
¹ =1.26¹ = 1.26
^-3 = 1.26^-3 =
Tishli g’ildirakdagi tishlar sonini aniqlashda yuqoridagi natijalar asosida [5] 6-jadvaldan Σz=90 ni tanlab olamiz va i₁=z₁/z₂ … i₉=z₁₅/z₁₆ formula orqali hisoblab chiqamiz.
Z₁=56; Z₂=34; Z₃=18; Z₄=72; Z₅= 39; Z₆=51;
Z₇=45; Z₈=45; Z₉=39; Z₁₀=51; Z₁₁=34; Z₁₂=56; Z₁₃=51; Z₁₄=39; Z₁₅=30; Z₁₆=60;
Endi shu hisob kitoblar asosida uzatishlar pog’onasining kinematik sxemasini quramiz:

5. Elektr dvigatel quvvatini xisoblash.
5.1 Frezaning maksimal diametri:
D_max=1*B_max=1*70=70mm
5.2 Maksimal frezalash chuqurligi
T_max=h (mm) h=5 mm
5.3 Frezaning tishlar soni:
(2.3.6-jadvaldan) z=8 ta
5.4 Frezalashda har bir tishga mos keluvchi surish miqdori:
(2.3.2-2.3.3 jadvaldan)
S_z1=0.14-0.18 mm/ayl
5.5 Frezaning turg‘unlik davri ;
T – 2.2.8 – jadval ;
T – 180 min
5.6 Kesish tezligi: ;
5.(2.3.7-jadvalda):
C_v=700; q_v=0.17; x_v=0.38; y_v=0.28;
= =199 m/min;
5.7 Kesish tezligi koeffitsenti:
Kv=K_mv*K_uv=1.4
5.8 Ishlov berilayotgan materialga bog‘liq koeffitsient:
K_mv – 2.3.10 jadval.
5.9 Kesuvchi asbobning kesuvchi qismi materialini xisobga oluvchi koeffitsient.
K_uv – 2.3.10-jadvaldan.
K_mv= 1.4; K_uv=1
5.10 Kesish tezligiga mos aylanishlar soni:

=792 ayl/min
5.11 Xaqiqiy kessish tezligi:

m/min
5.12 Frezalashda hosil bo‘ladigon kesish kuchi:

N
C_p=682; X_P=0.86; y=0.72; u_p=1; q_p=0.86;
5.13 N
5.14 Kesish kuchi koeffitsienti.
K_p- 2.1.9 – 2.1.10 - jadval.
5.15 Tezlika bog‘liq koeffitsient.
K_vp – 2.3.13 – jadval.
5.16 Maksimal quvvat.
N_max= 1.67*10^-5*P_z*V_x. (kvt)
N_max=1.67*10^-5*4519*174=13.13 kvt
5.17 Elektrodvigitelning zaruriy quvvati.
N_max=(0.6……0.7)* (kvt)
N_e=(0.6*13)/0.8=9.75 kvt

Endi esa hisob kitoblarim natijasiga ko’ra kerakli quvvatga mos dvigatel tanlab oldim.

Dvigatel markasi: 4A132S4
Quvvati: N_dv=11 Kvt Aylanishlar soni; 730-750 ayl/min.

6. Tezliklar uzatmasi qutisini konstruktiv o’lchamlarini aniqlash va mustahkamlikga hisoblash
Asosiy konstruktiv elementlarni aniqlash.
Vallarning quvvatini aniqlash:
N_i= N_dv*n_oi
n_oi=y*
y-0.96 surish qutisi uchun sarflanadigan quvvat koeffitsenti
ⁱ-0.96 tasmali uzatmadagi yo’qotish
ⁱ- 0.99 poshivmiklar uchun yo’qotish
ⁱ-0.99 tishli uzatmalar uchun yo’qotish
Vallardagi burovchi Moment:

n_mini- I valdagi minimal aylanishlar soni

r-ruxsat etilgan kuchlanish; r=20 MPa

6.1) 1 -valdagi quvvatni aniqlaymiz.
N_i= N_dv*n_oi=3.76
6.1.1) =0.99*0.99=0.98
6.1.2) =098*0.99*0.99=0,96
6.1.3) =0.96*0.99*0.99=0,94
6.1.4) =0.94*0.99⁴*0.99⁴=0,92

6.2 Hosil bo‘lgan quvvatlardan foydalangan holda.
Vallardagi quvvat

N ₁= 11 * 0.98 = 10.78

N ₂= 11 * 0.96 = 10.56
N ₃= 11 * 0,94= 10.34
N ₄= 11 * 0,92= 10.12

Hosil bo‘lgan quvvatlardan foydalangan holda.

Formula bo‘yicha har bir valdagi maksimal momentni hisoblab chiqaramiz.
6.2.1) =141 N*m
6.2.2) =862 N*m
6.2.3) =1335 N*m
6.2.4) =2613 N*m
6.3) Vallarning tishli g`ildirak osti diametrini aniqlaymiz:
d_i= bo’yicha val diametrlari hisoblanadi.
=20 MPa(1-jadval) bu yerda har bir valdagi maksimal moment.
6.3.1) *10 = 32 mm
6.3.2) *10 = 60 mm
6.3.3) *10 = 70 mm
6.3.4) *10 = 86 mm

6.4) 1-jadvaldagi qiymatlardan foydalanib M_Fi ni M_Fi = M_imax * K_fv K_fb dan topamiz. Buyerda K_fv =K_fb= 1.20 ga teng va n_imin ning qiymati aylanish chastotalar grafigidan tanlandi.
6.4.1) M_F1 = M_1max * K_fv K_fb= 141*1*1.20= 169 N*m
6.4.2) M_F2 = M_2max * K_fv K_fb= 862 *1*1.20= 1034 N*m
6.4.3) M_F3 = M_3max * K_fv K_fb= 1335 *1*1.20= 1602 N*m
6.4.4) M_F4 = M_3max * K_fv K_fb= 2613*1*1.20= 3135 N*m
6.5 Tishli g’ildiraklarning ilashish modulini aniqlash.

Ψ=8 Tishli g‘ildiraklarni enni hisobga oluvchi koeffitsent;
Y_Fi- Tish xolatini hisobga oluvchi koeffitsent 9-jadvaldan
Z_i= burovchi moment kata bo‘lgan tishlar soni.
M_Fi=M_imax*K_Fv*K_Fb
6.5.1) m₁ = =
6.5.2) m₂ =
6.5.3) m₃ =
6.5.4) m₄ =
m_o‘rt= = 5
vallar uchun standart qatordan m=5 modulni tanlab oldim.


6.6 Tishli g’ildirakning konstuktiv o’lchamlari.
Bo’luvchi diametr – d_i=m*z
Tashqi diametr – d_ai=d_i+2m
Ichki diametr – d_fi=d_i-2.5m
Vallar orasidagi masofa – A_w=Zum*m/2.

d₁=5*56=280 d_a1=280+10=290 d_f1=280-12.5=167.5

d₂=5*34=170 d_a2=170+10=180 d_f2=170-12.5=157.5
d₃=5*18=90 d_a3=90+10=100 d_f3=90-12.5=77.5
d₄=5*72=360 d_a4=360+10=170 d_f4=360-12.5=347.5
d₅=5*39=195 d_a5=195+10=205 d_f5=195-12.5=182.5
d₆=5*51=255 d_a6=255+10=265 d_f6=255-12.5=242.5
d₇=5*45=225 d_a7=225+10=235 d_f7=225-12.5=212.5
d₈=5*45=225 d_a8=225+10=235 d_f8=225-12.5=212.5
d₉=5*39=195 d_a9=195+10=205 d_f9=195-12.5=182.5
d₁₀=5*51=255 d_a10=255+10=265 d_f10=255-12.5=242.5
d₁₁=5*34=170 d_a11=170+10=180 d_f11=170-12.5=157.5
d₁₂=5*56=280 d_a12=280+10=290 d_f12=280-12.5=167.5
d₁₃=5*51=255 d_a13=255+10=265 d_f13=255-12.5=242.5
d₁₄=5*39=195 d_a14=195+10=205 d_f14=195-12.5=182.5
d₁₅=5*30=150 d_a15=150+10=160 d_f15=150-12.5=137.5
d₁₆=5*60=300 d_a16=300+10=310 d_f16=300-12.5=287.5
Vallar orasidagi masofa:
Aw=90*5/2=225
Shponka tanlash:
3-val uchun
Val diametri d=53 ga mos shponka razmerlarini jadvaldan tanlab olamiz
b=10
L=36…160
1-val uchun
Val diametri d=40 ga mos shponka razmerlarini jadvaldan tanlab olamiz
b=8
L=28 … 140



Podshipnik tanlash
Val diametriga mos podshivniklarni jadvaldan o’lchamlarini tanlab oldik
1-val uchun
Val diametri d_v=40 bolgani uchun bunga standart qatordan
308 markali ya’ni ichki diametri 40 ga teng bo’lgan podshipnik tanlab oldik va o’lchamlarini tanlab oldik
d=40; D=90; B=23 r=2.5;
2-val uchun
Val diametri d_v=40 bolgani uchun bunga standart qatordan
308 markali ya’ni ichki diametri 40 ga teng bo’lgan podshipnik tanlab oldik va o’lchamlarini tanlab oldik
d=40; D=90; B=23; r=2.5;
3-val uchun
Val diametri d_v=53 bolgani uchun bunga standart qatordan
310 markali ya’ni ichki diametri 50 ga teng bo’lgan podshipnik tanlab oldik va o’lchamlarini tanlab oldik
d=50; D=100; B=27; r=3;
4-val uchun
Val diametri d_v=55 bolgani uchun bunga standart qatordan
310 markali ya’ni ichki diametri 50ga teng bo’lgan podshipnik tanlab oldik va o’lchamlarini tanlab oldik
d=50; D=100; B=27; r=3;

Podshipnik uchun Qopqoq tanlash
Podshivnik tashqi diametriga qarab jadvaldan unga mos qopqoq o’lchamlarini ko’chirib, shular asosida qopqoq yasaymiz.
1-podshipnik uchun: qopqoq;
D=90; D₁=100; D₂=130; D₃=80;
d=9; d₁=15; d₂=20; n=6
H=12; H₂=20; h₁=8; b=4;
2-podshipnik uchun
D=90; D₁=100; D₂=130; D₃=80;
d=9; d₁=15; d₂=20; n=6
H=12; H₂=20; h₁=8; b=4;
3-podshipnik uchun
D=120; D₁=120; D₂=145; D₃=90;
d=11; d₁=18; d₂=24; n=6
H=15; b=5;

4-podshipnik uchun

D=120; D₁=120; D₂=145; D₃=90;
d=11; d₁=18; d₂=24; n=6
H=15; b=5;
Qopqoqni mahkamlash uchun vint tanlash
Bunda hamma qopqoq uchun standart ikkita vintdan foydalandim. Bu vint o‘lchamlarini standartdan qopqoq diametriga asoslanib tanlab oldim.
D<100 bo’lgani uchun M8 va M10 markali vint tanlab oldim.
D=13; H=5.5; b=2; h=2.5; l=12…70(22)
Shlitsa tanlash
2-Val diametri d=44 ga mos 6x38x44 shlitsa tanlab oldim. O’lchamlarini jadvaldan oldim.
4-Val diametri d=56 ga mos 8x50x56 shlitsa tanlab oldim. O’lchamlarini jadvaldan oldim.
Shponkani mustaxkamlikka sinash;
1-valni

=170 MPa
=0.2*
3-valni;

= =0.32*