3-mavzu. MatriTsalar
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Matematikadan o’quv-uslubiy majmua
- Bu sahifa navigatsiya:
- 1.5. 1.6. 1.7. 1.8. 1.9. va
- 1.13. 1.14. 1.15. 1.16. 1.17.
1- AMALIY MASHG‘ULOT
1.1. kvadrat matritsa bo‘lsin. simmetrik matritsa bo‘lishini ko‘rsating. 1.2. matritsani va matritsalarning chiziqli kombinatsiyasi ko‘rinishida ifodalang. 1.3. bo‘lsa, va ni toping. 1.4. Matritsa 30 ta elementga ega bo‘lsa, u qanday tartiblarda berilishi mumkin? 1.5-1.1.8 masqlarda matritsalar va sonlar berilgan. matritsani toping: 1.5. 1.6. 1.7. 1.8. 1.9. va moslashtirilgan matritsalar bo‘lsin. Quyidagilarni ko‘rsating: (a) agar matritsa satr matritsa bo‘lsa, u holda satr matritsa bo‘ladi; (b) agar matritsa ustun matritsa bo‘lsa, u holda ustun matritsa bo‘ladi. 1.10. bo‘lsa, va ni toping. 1.11. Agar matritsa o‘lchamli va esa o‘lchamli bo‘lsa, ko‘paytma ma’noga ega bo‘lishi uchun matritsa qanday o‘lchamda bo‘lishi kerak? 1.12. matritsa berilgan. ko‘paytmani nol matritsaga aylantiruvchi matritsani toping. 1.13-1.1.16 mashqlarda va matritsalar berilgan. matritsani toping: 1.13. 1.14. 1.15. 1.16. 1.17. bo‘lsa, matritsani toping. 1.18. bo‘lsa, matritsani toping. 1.19. matritsalar berilgan. matritsalarni toping. 1.20. va bo‘lsin. ni toping. 1.21. bo‘lsa, ni toping. 1.22. Agar va matritsa o‘lchamli bo‘lsa, ni toping. 1 Lay, David C. Linear algebra and is applications. Copyright. 2012, pp. 92-112 2 Lay, David C. Linear algebra and is applications. Copyright. 2012, pp. 92-112 3 Lay, David C. Linear algebra and is applications. Copyright. 2012, pp. 92-112 4 E.Kreyszig. Advancet engineering Matematics. Copyright. 2011, pp. 255-265 4 5 E.Kreyszig. Advancet engineering Matematics. Copyright. 2011, pp. 255-265 6 Lay, David C. Linear algebra and is applications. Copyright. 2012, pp. 92-112 7 E.Kreyszig. Advancet engineering Matematics. Copyright. 2011, pp. 255-265 8 E.Kreyszig. Advancet engineering Matematics. Copyright. 2011, pp. 255-265 Download 0.91 Mb. Do'stlaringiz bilan baham: |
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