Modellashtirish.
3 –sinfdagi xarakatgadoir masalalarasosanmasofadagibog`liqbo`ladi. Tezlik tushunchasi bu sinfdagikiritilmaydi .
3 – sinfdagixarakatgadoir masalalarnimodel asosidayechishningmisollarkeltiraylik. 326misol ( 78- bet)
Velisopedchi qishloqqacha20 km,qishloqdan keyin 4 marta kam yo`l yuradi.
Velisopedchi hammasibo`lib necha kilometr yo`l yurgan ?
Yechish:
1 – model
20+20’4=Masofa
1) Qishloqdankeyinvelosipetdagiqancha yo`l yurgan ? 20: 4 = 5 yil
2)Xammasibolib, qancha yo`lyurgan ?
20 + 20: 4 = 25 km
J:25 km 2 – model a + a: c
368 – masala ( 89 bet)
Sonlarni500 gachato`ldring:420, 480,440, 410.
Sonlarni900 gacha to`ldring:860, 830, 870,820.
1 – model
150 km
60 km 70 km
2 – model
mash +20
60 70
1)Ikkalamashinaqancha yo`l yurgan ?
60 + 70 =130km
2)Qolganmasofaqancha ?
150 – 130 = 20 km
3 – model a-( b + c)
425 m- masala( 102 bet)
Do`kon,kinoteatrva maktabko`chaningbir tomonidanjoylashgan. Do`konda kinoteatrgacha900 m,kinoteatrdanmaktabgacha200 mkam.
Do`kondamaktabgachabo`lganmasofaqancha ?Shartbo`yichaturlichizmalar tuzingva masala yeching.
Yechish:
– model
Do`konkinoteatrmaktab
– model
+ =
1)Kinotetrdan maktabgacha necha metr ?
900 – 200 =700 m
2)Do`kondanmaktabgachamasofa qancha ?
900 +700 =1600 m
Javob:1600 m 3 – model
a + ( a - b)
675 -masala( 160 bet)
Ikkita matorliqayiqbir manzildanqarama – qarshi tomongaqarab jo`nashdi.Ulardanbiri 38 km,ikkinchisi undan5 kmortiq yo`l bosdi.Shuvaqtda qayiqlar bir – biridan qanchamasofadabo`lgan ?
Yechish:
1 – model
38 km38 + 5
2 – model
+ =
1)Ikkinchi qayiqqancha masofayurdi ?
38 + 5 =43
2)Ularorasidagimasofaqancha ?
38 +43=81 km
Javib:81 km
3 – model a + (a + b)
Do'stlaringiz bilan baham: |