7-dars Mustaqil yechish uchun misol va masalalar 1-misol
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Mustaqil yechish uchun misol va masalalar e5571dd1ee6c358cbd20fa5691580cfc
7-dars Mustaqil yechish uchun misol va masalalar 1-misol. 1) Πgar Π= 1 2
3 4 , π΅ = 4 β4 0 1
2) Πgar Π =
1 β1 0 2 1 1 3 β1 2
, Π = Π = β2 1 2 0 4 5 2 β3 7 boβlsΠ°, Π+Π, 3Π , ΠΠ, ΠΠ larni toping.
2-msol.. Πmallarni bajaring. 1)
1 2 β2 1 3 β1 1 1 β2 3 5 β2
1 β2 4 2 3 2 3 1 4 ; 2) 2 1
4 2 1 β2 1 1 2 β3 1 1 2 β1 ;
3) 1 β3 3 β1 1 3
1 1 1 2 1 1 1 β2 ; 4) 1 β2 4 6 0 7 8 2 6 β3 ; 5)
1 2 8 3 4 ; 6) 2 β1 2 9 .
3-misol. βπ β π uchun quyidagilarni toping. 1) 5 β4
6 β5
π ; 2) 2 β1 3 β2
π ; 3) 1 1 0 1
π ; 4)
πππ π βπ πππ π πππ πππ π
π ; 5) 2 1 0 0 1 0
0 0 2
π . 4-misol. Πgar πΌ β π boβlsa, lim πββ
1 πΌ π β πΌ π 1
π = cos πΌ sin πΌ β sin πΌ cos πΌ tenglikni isbotlang. 5.5. π(π΄) ni hisoblang: 1) π΄ = 1 β1 2 1 ; π π₯ = π₯ 2 β 5π₯ + 7 ; 2) π΄ =
1 β1 1 2 0 β2 3 3 3 ; π π₯ = 3π₯ 2 β 7π₯ β 4 ; 3) π΄ =
β2 0 1 0 1 β2 1 β2 0 ; π π₯ = π₯ 3 β 2π₯ 2 + 3π₯ β 4 . 6-misol. 1) Πgar π΄ =
1 1 0 0 2 1
0 0 2 , πΌ = 1 0 0 0 1 0
0 0 1 boβlsΠ°, π΄ β 2 β πΌ 2 (π΄ β πΌ) ni toping. 2) Agar π΄ = β1 3 4 1
0 1 boβlsΠ°, π΄ 2 β 12 β πΌ ni toping. 1) Πgar π΄ = 0 1
0 1 , πΌ = 1 0 0 1 boβlsΠ°, π΄ 2 β π΅
2 ni toping.
1)
(π΄ + π΅) 2 = π΄ 2 + 2π΄π΅ + π΅ 2 ; 2) π΄ 2 β π΅
2 = π΄ + π΅ (π΄ β π΅) tengliklarni isbotlang. Download 462,67 Kb. Do'stlaringiz bilan baham: |
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