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35. The correct answer is (C). [0] Given the restrictions on x, since cos x = –1, x must equal 
π(180°).
And cos 
π
2
= 0.
You can also reach this same conclusion if you visualize a graph of the cosine function:
36. The correct answer is (B). [–] Sketch a graph of the function:
The function cannot generate the value –1 because 
1
x
cannot have the value 0.
37. The correct answer is (E). [0] Since x = 3 sin 
θ and y = 2 cos θ, sin θ = 
x
3
and cos 
Θy
2
. Since
sin
2
θ + cos
2
θ = 1:
And the equation:
is the equation of an ellipse with center (0,0) that passes through the points (3,0) and (0,2)

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Lesson 8
244
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Alternatively, you could try some values for 
θ:
θ = 0
x = 3 sin 0 = 3(0) = 0
y = 2 cos 0 = 2(1) = 2
θ =
π
2
x = 3 sin
π
2
= 3(1) = 3
y = 2 cos
π
2
= 2(0) =0
So the graph must include the points (3,0) and (0,2). The only graph given that contains both of those
points is (E).
38. The correct answer is (E). [+] To find x, take the log of both sides of the equation:
39. The correct answer is (C). [+] Put your calculator in the radian mode. Since 4 cos x = sin x, sin x/
cos x = 4. But since 
sin
cos
x
x
= tan x (by Quotient Identity), tan x = 4. The value of x is the inverse
tangent of 4:
x = tan
–1
4 = 1.3258 or 1.326.