Branish konturi chastotaviy tavsiflari xususiyatlarini eksp
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Kеtma-kеt tеbranish konturi chastotaviy tavsiflari xususiyatlarini ekspеrimеntal tеkshirish. L=50mGn C=93nF U=1V., Rd =100 Chastotani hisoblaymiz: fo =1/(2π√LC)=1/(2*3,14*√(50*10-3*93*10-9))=2335 Hz; Iw1 = U/Z=1/(1002+(2*3,14*1735*0,05-1/(2*3,14*1735*93*10-9))2)- 1/2=1,8mA Iw2 = U/Z=1/(1002+(2*3,14*1935*0,05-1/(2*3,14*1935*26*10-9))2)- 1/2=1,6mA Iw3 = U/Z= 1/(1002+(2*3,14*2135*0,05-1/(2*3,14*2135*26*10-9))2)- 1/2=1,5mA; Iw4 = U/Z= 1/(1002+(2*3,14*2335*0,05-1/(2*3,14*2335*93*10-9))2) - 1/2=1.4mA; Iw5 = U/Z=1/(1002+(2*3,14*2535*0,05-1/(2*3,14*2535*93*10-9))2)- 1/2=1,24mA Iw6 = U/Z=1/(1002+(2*3,14*2735*0,05-1/(2*3,14*2735*93*10-9))2)- 1/2=1,2mA Iw7 = U/Z=1/(1002+(2*3,14*2955*0,05-1/(2*3,14*2935*93*10-9))2)- 1/2=1,1mA Qarshilikdagi kuchlanishni hisoblaymiz: UR(wn)=I(wn)R UR1 =100* 1,8mA=0,18V UR2 =100* 1,6mA=0,16V U R3 =100* 1,5mA=0,15V UR4 =100* 1,4mA=0,14V UR5 =100* 1,24mA=0,124V UR6 =100* 1,2mA=0,12V UR7 =100* 1,1mA=0,11V Induktivlikdagi kuchlanishni hisoblaymiz: UL(wn)=I(wn)wnL UL1 =0,5*1,8*10-3*2*3,14*1735=9,81V UL2 =0,5*1,6*10-3*2*3,14*1935=9,7V UL3 =0,5*1,5*10- 3*2*3,14*2135=10,1V Download 129.34 Kb. Do'stlaringiz bilan baham: |
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