Dualisme Cahaya Sebagai Gelombang dan Partikel
Download 107.21 Kb. Pdf ko'rish
|
- Bu sahifa navigatsiya:
- Spectrum of electromagnetic radiation
- Graphical presentations
- Failure of classical theory
- 1.3.1 What is blackbody
- Phenomena for a blackbody
- Temperature dependence of emission spectrum
- Blackbody radiation – Stefan’s Law
- Blackbody radiation and ultra-violet catastrophe
- UV catastrophe
- Plancks derivation of blackbody radiation
Dualisme Cahaya Sebagai Gelombang dan Partikel Fisika Modern Wave Properties Light intensity = ?????? ∝ ?????? 2
Particle Properties Light intensity: ?????? = ??????ℎ?????? Quantum Theory of Light Under a constant frequency, the smallest energy unit of light is quantized. Fisika Modern For one photon For N photon I= ??????ℎ??????
?????? = ℎ?????? = ℎ?????? ??????
Fisika Modern Spectrum of electromagnetic radiation Free electrons in resonance Transition of bound electrons in atoms Nucleus
Fisika Modern 1.3.2 Photoelectric effect http://lectureonline.cl.msu.edu/~mmp/kap28/PhotoEffect/photo.htm Fisika Modern Photoelectric effect applet
Photoelectric effect applet Fisika Modern Einstein’s interpretation
Under a constant frequency, the smallest energy unit of light is quantized. One photon can at most release one electron, regardless of the photon energy
Fisika Modern Work Function, W– the minimum energy for electron to escape from the metal surface
where K is the kinetic energy of the photoelectron Photocurrent nq I p where is the quantum efficiency, n number of photons striking to the electrode per second, q electron charge Fisika Modern The number of photons striking to the electrode is related to the light intensity I
by
h A I n L Where A is the area of the electrode exposed to light. Fisika Modern Threshold frequency When K = 0, there is no photoelectrons. The frequency reaches the threshold frequency, i.e.
Fisika Modern Stopping voltage The reverse biasing voltage: where the photoelectrode is positively biased and the other negatively biased. When the biasing voltage increases from zero, the photocurrent decreases. At V V S , I P = 0
Fisika Modern Stopping voltage S qV K 0 v The physical meaning is that the potential difference barrier is decelerating the electron, and finally consumes all its kinetic energy. Thus, the stopping voltage gives us a tool to determine the kinetic energy, mgh 2 2 1 mv K qV S Fisika Modern Stopping voltage against frequency W h K qV S
W q h V S Stopping Voltage V
Slope = / h q o Fisika Modern Observations • Monochromatic light is incident to one of the electrodes made by a particular metal. The induced current called photocurrent is collected. • If V is fixed, there exists a threshold frequency o
• Different electrode materials have threshold frequency o
Fisika Modern Observations • The photocurrent is constant above the threshold frequency under a constant illumination, regardless of the frequency. • The photocurrent is proportional with the intensity. • The energy of electron is proportional with the frequency. • For a particular electrode and frequency of light, a stopping voltage V
collected regardless of the intensity of light. • There is no measurable tie lag between the illumination of light and the release of photoelectrons. (10 -9 s)
Fisika Modern Graphical presentations Energy of photoelectrons is proportional to the frequency; Existence of threshold frequency
o
Fisika Modern Photocurrent is proportional to light intensity
Fisika Modern Different frequency of light has different stopping voltage
Fisika Modern Stopping voltage varies with (1)electrode material for the same frequency (2) increases with frequency of light for the same electrode Fisika Modern Example:
Cahaya ultraviolet dengan panjang gelombang 350 nm dan intensitas 1 W/m 2
mengenai permukaan elektroda yang “work function” nya 2.2 eV. a. Hitung energi kinetik elektron yang dilepas oleh elektroda tersebut. b. Jika 1% dari photon yang datang diubah menjadi fotoelektron, berapa jumlah elektron yang dilepas per detik jika luas permukaan 1 cm 2
Diketahui konstanta Planck =6.626x10 −34
Js = 4.136x10 −15
eVs Fisika Modern Failure of classical theory • In 1902, Philipp Eduard Anton von Lenard observed that the energy of the emitted electrons increased with the frequency of the light. This was at odds with James Clerk Maxwell's wave theory of light, which predicted that the energy would be
Fisika Modern • Within the experimental accuracy, (about 10 -9
of photoelectrons. In terms of wave theory, the energy is uniformly distributed across its wavefront. A period of time is required to accumulate enough energy for the release of electrons.
Fisika Modern 1.3.1 What is blackbody? • Under thermal equilibrium, an object of a finite temperature emit radiation (supposed to be EM wave).
• It is found that an object that absorbs more also emits more radiation. • A perfect absorber is an object with black surface that must of the incident energy is absorbed. It is also expected to be a perfect radiator. • Consequently, a blackbody is a perfect radiation.
Fisika Modern Phenomena for a blackbody • Temperature-dependence emission spectrum. • Reciprocal relation between wavelength at the peak intensity max
and ambient temperature T • Inconsistency between observed spectrum and the prediction from classical theory (Reyleigh and Jeans) • A model suggested by Planck (quanta of light energy) Fisika Modern Inconsistency of Classical wave theory and experiment 4 8 ~ kT I 1 ) / exp(
1 8 5
hc hc Fisika Modern Temperature dependence of emission spectrum http://surendranath.tripod.com/AppletsJ2.html http://webphysics.davidson.edu/alumni/MiLee/java/bb_mjl.htm
Fisika Modern Classic: Rayleigh – Jeans Formula Planck Radiation ?????? = ?????? ?????? ??????
Total Energy in the cavity with frequency interval between v and v+dv ?????? ?????? ???????????? = ?????? ?????? ?????? ???????????? = 8???????????? ??????
?????? ??????
3 ??????
2 ???????????? ?????? = ℎ??????
exp ℎ??????
?????? ??????
?????? − 1
?????? ?????? ???????????? = ?????? ?????? ?????? ???????????? = 8??????ℎ ??????
3 ??????
3 exp
ℎ?????? ??????
?????? ?????? − 1 ????????????
Fisika Modern Inconsistency of Classical wave theory and experiment 4 8 ~ kT I 1 ) / exp(
1 8 5
hc hc Blackbody radiation – Stefan’s Law An object having a surface temperature T will emit radiation power P which is proportional to the surface area A of the object and to the fourth power of the temperature. 4
is the Setfan’s constant and is equal to 5.67 x 10 -8 Wm
-2 K -4 (Jm -2 s -1 K -4 ) is the emissivity of the object and is 1 0 Fisika Modern Fisika Modern Wein displacement Law Fisika Modern -Hitung panjang gelombang yang dipancarkan tubuh anda
- Berapa energi yang dipancarkan oleh tubuh anda? Blackbody radiation and ultra-violet catastrophe
as we do the integration Blackbody radiation and ultra-violet catastrophe
From Maxwell E.M. theory we know that a dipole oscillating with frequency will on average emits energy r ( ) E E r ( ) = const. 2
where
is the average energy of the oscillating dipole. Rayleigh - Jean's Law
Maxwell-Boltzman distribution gives the energy state number density N(E) at energy E as kT E e E N / ) (
total number of possible energy state 0 ) ( dE E N and
Total energy 0 ) ( dE E EN Hence the average energy: states energy of number Total nergy Totale E . . . . . kT e dE Ee dE E N dE E EN kT E kT E 0 / 0 / 0 0 ) ( ) ( r() Rayleigh-Jeans Blackbody radiation UV catastrophe
Fisika Modern This result is in fact well known from kinetic theory where the energy of vibrational degree of freedom
So now we have r()
Const. 2 T
Rayleigh-Jeans Law describes the beginning part of the blackbody radiation correctly at low frequency (long wavelength) but it obviously wrong at high . As increases r()
r() , the
radiate energy goes to infinity!
The energy of rotational / bending degree of freedom kT 2 1 kT 0 This is called UV catastrophe. Ultra-violet catastrophe Fisika Modern kT e dE Ee dE E N dE E EN E kT E kT E
0 / 0 / 0 0 ) ( ) ( 0 / 0 / 0 0 0 n kT nE n kT nE e e nE E .....
1 .....
3 2 0 / 3 / 2 / / 3 0 / 2 0 / 0 0 0 0 0 0 0 kT E kT E kT E kT E kT E kT E e e e e E e E e E ( ) 1 1 x ( ) 2 1 x ..... 1 .....
3 2 1 2 2 0 x x x x x E E kT E e x / 0 ) 1 ( 0 x x E ) 1 1 ( 0 x E 1 / 0 0 kT E e E E Planck's derivation of blackbody radiation
Rayleigh - Jean's Law:
This integration assume continuous distribution of energy, i.e. the oscillator can take up any value. Plank made the hypothesis that the oscillator will only take up discrete energies 0, E
0 , 2E
0 , 3E
0 , .....etc.
the average energy is obtained from a summation instead of integration.
Let
Fisika Modern Fisika Modern Blackbody radiation http://surendranath.tripod.com/Applets.html Fisika Modern Conclusion • Rayleigh – Jeans ‘s derivation is only valid at long wavelengths (low frequencies) and fails at short wavelength. • Planck made an assumption: energy emitted from the radiator at a frequency , E = nh
, where n and integer, h the Planck constant (energy is discretized) • Implication: classical theory predicts energy is continuous
Download 107.21 Kb. Do'stlaringiz bilan baham: |
ma'muriyatiga murojaat qiling