Fozilova Sadoqat Ibrohim qizi Kimyodan masalalar yechish fanidan Mustaqil ta`limi

7-masala. 30 gr NaCl 90 gr suvda eritildi. Eritmaning massa ulushini toping
m=30+90=120gr
ω=30/120*100%=25%
8-masala. 0,5 mol NaCl bor 300gr eritmada Na ning massa ulushini aniqlang
0,5 mol----------x=29,25 gr NaCl
1mol----------58,5gr

29,25 gr---------x=11,5 gr

58,5 gr----------23

(11,5/300)*100%=3,83%

9-masala. 3 mol CaCl₂ bor 400gr eritmada Ca ning massa ulushini aniqlang
3 mol-----------x=333gr CaCl₂
1mol-----------111

333gr-----------x=120 gr
111------------40gr Ca

(120/400)*100%=30%

10-masala. Birikmaning formulasini toping. X₂O₅
M₀= 5,55*10^-22/1,66*10^-24=334
334-80=254
254/2=127 yod I
Javob: I₂O₅
11-masala. Absolut massasi 1,59*10²³ bo`lgan element atomini toping
1,59*10<sup>23</sup>*6,02*10<sup>23</sup>=96 Mo
12-masala. III valentli nomalum element hosil qilgan oksidning ekvivalent massasi=12,667. Elementni toping
E<sub>2</sub>O<sub>3</sub>
Mr=12,667*2*3=76
76-48=28
28/2=14 N azot
13-masala. ω O<sub>2</sub> =96% bo`lgan vodorod va kisloroddan iborat gazlar aralashmasining o`rtacha Mr=?
100--------100%
X=96---------96%
96/32=48
4/32=2,125
100/5=25
14-masala. ω H<sub>2</sub>=20% bo`lgan vodorod va kisloroddan iborat gazlar aralashmasining o`rtacha Mr=?
100-------100%
X=20--------20%
X=80----------80%
20/2=10
80/32=2,5
100/12,5=8
15-masala. ω H<sub>2</sub>=60% bo`lgan vodorod va kisloroddan iborat gazlar aralashmasining o`rtacha Mr=?
100------------100%
X=60-----------60%
X=40-----------40%
60/2=30
40/32=1,25 1mol-------100%
X=0,6 mol-----60%
X=0,4mol-------40%
0,6*2=1,2
0,4*32=12,8
12,8+1,2=14/1=14