Ko`phadlarni ko`paytuvchilarga ajratish usullari. Reja


c) x(x – y) + y(y – x) – 3(x – y)


Download 20.83 Kb.
bet5/5
Sana18.06.2023
Hajmi20.83 Kb.
#1579801
1   2   3   4   5
Bog'liq
Ko\'phadlarni ko\'paytuvchilarga ajratishning turli usullari

c) x(x – y) + y(y – x) – 3(x – y) .

Ko'phadning ikkinchi hadidagi (y – x) ifodani – (x – y) ko'rinishida yozib olamiz:

x(x – y) + y(y – x) – 3(x – y) = x(x – y) – y(x – y) – 3(x – y) .

(x – y) umumiy ko'paytuvchini qavsdan tashqariga chiqaramiz:

x(x – y) – y(x – y) – 3(x – y) = (x – y)(x – y – 3) .

d) 2x(a – 2) + 4y(2 – a) + 6z(2 – a) .

Ko'phadning ikkinchi va uchinchi hadlaridagi (2 – a) ifodani – (a – 2) ko'rinishida yozib olamiz:

2x(a – 2) + 4y(2 – a) + 6z(2 – a) = 2x(a – 2) – 4y(a – 2) – 6z(a – 2) .

2(a – 2) umumiy ko'paytuvchini qavsdan tashqariga chiqaramiz:

2x(a – 2) – 4y(a – 2) – 6z(a – 2) = 2(a – 2)(x – 2y – 3z) .






Download 20.83 Kb.

Do'stlaringiz bilan baham:
1   2   3   4   5




Ma'lumotlar bazasi mualliflik huquqi bilan himoyalangan ©fayllar.org 2024
ma'muriyatiga murojaat qiling