Matematika. Hisoblang


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Matematika.
1. Hisoblang.
A) 30 B) 33 С) 34 D) 40
2. Hisoblang: 50·204:12.
А) 845; В) 755; C) 295; D) 850.
3. Hisoblang.
A) 200 B) 100 C) 50 D) 250
4. Yig'indini hisoblang.
A)1830 B) 121 C) 3660 D) 1810
5. Qaysi tenglik qoldiqli bo'lishni ifodalaydi?
A) 129 =26·5-1; B) 129 =24·5+9;
C) 129 =5·24+9; D) 129 =23·5+15.
6. 358 ni qanday songa bo'lganda bo'linma 17 va qoldiq 1 bo'ladi?
A) 19; В) 21; C) 22; D) 20.
7. 215 ni 19 ga bo'lganda, qoldiq 6 ga teng bo'ldi. To'liqsiz bo'linmani toping.
A) 13; . В) 12; C) 9; D) 11.
8. 8 ga bo’linganda 3, 12 ga bo’linganda 7,
15 ga bo’linganda 10 qoldiq qoladigan sonni toping.
A) 160 B) 151
C) 125 D) 115
9. Ifodaning qiymatini toping:
(23 - 22) • (42 - 15).
A) 16; В) 23; C) 15; D) 4.
10. ni toping
A) 18 B) 27 C) 54 D) 3240
11. ni sm da ifodalang.
A) 7003446 B) 7034046
C) 703446 D) 70003446
12. ni toping
A) 6 B) 120 C) 240 D) 40
13. Murod va Sanjarda jami 62 ta olma bor. Murod va Oybekda jami 54 ta , Sanjar va Oybekda jami 48 ta olma bor. Savol: Oybekda nechta olma bor?
A) 20 ta B) 24 ta C) 27 ta D) 34 ta
18. ning qiymatini toping.
A) 24; В) 18; C) 48; D) 10.
19. 1;2; 3; 15; 17; 23; 28; 49; 67; 121; 303; 324; 1001 sonlar ichida nechta tub son bor?
A) 4; В) 5; C) 6; D) 7.
20. 36 sonining natural bo'luvchilari nechta?
A) 5; В) 7; D) 8; Е) 9.
21. Hisoblang.

A) 310 B) 1200
C) 600 D) 450
23. yig’indini 6 ga bo’lgandagi qoldiqni toping.
A) 1 B) 5 C) 3 D) 0
24. Dastlabki 100 ta natural sonni yozganda 7 raqami necha marta takrorlanadi.
A) aniqlab bo’lmaydi B)11 C) 20 D)12
25. Natural sonni 9 ga bo'lganda bo'linma 20, qoldiq 11 ga teng. Shu sonni toping.
A) 169 B) 191
C) 176 D) bunday son yo'q
26. yig’indini oxirgi raqamini toping.
A) 0 B) 2 C) 4 D) 6
27. yig’indini oxirgi raqamini toping.
A) 0 B) 2 C) 4 D) 6
28. ayirmani oxirgi raqamini toping.
A) 0 B) 2 C) 4 D) 6
29. yig’indini oxirgi raqamini toping. A) 0 B) 5 C) 4 D) 6




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