Matematika. Hisoblang
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Matematika TAKROR
Matematika. 1. Hisoblang. A) 30 B) 33 С) 34 D) 40 2. Hisoblang: 50·204:12. А) 845; В) 755; C) 295; D) 850. 3. Hisoblang. A) 200 B) 100 C) 50 D) 250 4. Yig'indini hisoblang. A)1830 B) 121 C) 3660 D) 1810 5. Qaysi tenglik qoldiqli bo'lishni ifodalaydi? A) 129 =26·5-1; B) 129 =24·5+9; C) 129 =5·24+9; D) 129 =23·5+15. 6. 358 ni qanday songa bo'lganda bo'linma 17 va qoldiq 1 bo'ladi? A) 19; В) 21; C) 22; D) 20. 7. 215 ni 19 ga bo'lganda, qoldiq 6 ga teng bo'ldi. To'liqsiz bo'linmani toping. A) 13; . В) 12; C) 9; D) 11. 8. 8 ga bo’linganda 3, 12 ga bo’linganda 7, 15 ga bo’linganda 10 qoldiq qoladigan sonni toping. A) 160 B) 151 C) 125 D) 115 9. Ifodaning qiymatini toping: (23 - 22) • (42 - 15). A) 16; В) 23; C) 15; D) 4. 10. ni toping A) 18 B) 27 C) 54 D) 3240 11. ni sm da ifodalang. A) 7003446 B) 7034046 C) 703446 D) 70003446 12. ni toping A) 6 B) 120 C) 240 D) 40 13. Murod va Sanjarda jami 62 ta olma bor. Murod va Oybekda jami 54 ta , Sanjar va Oybekda jami 48 ta olma bor. Savol: Oybekda nechta olma bor? A) 20 ta B) 24 ta C) 27 ta D) 34 ta 18. ning qiymatini toping. A) 24; В) 18; C) 48; D) 10. 19. 1;2; 3; 15; 17; 23; 28; 49; 67; 121; 303; 324; 1001 sonlar ichida nechta tub son bor? A) 4; В) 5; C) 6; D) 7. 20. 36 sonining natural bo'luvchilari nechta? A) 5; В) 7; D) 8; Е) 9. 21. Hisoblang. A) 310 B) 1200 C) 600 D) 450 23. yig’indini 6 ga bo’lgandagi qoldiqni toping. A) 1 B) 5 C) 3 D) 0 24. Dastlabki 100 ta natural sonni yozganda 7 raqami necha marta takrorlanadi. A) aniqlab bo’lmaydi B)11 C) 20 D)12 25. Natural sonni 9 ga bo'lganda bo'linma 20, qoldiq 11 ga teng. Shu sonni toping. A) 169 B) 191 C) 176 D) bunday son yo'q 26. yig’indini oxirgi raqamini toping. A) 0 B) 2 C) 4 D) 6 27. yig’indini oxirgi raqamini toping. A) 0 B) 2 C) 4 D) 6 28. ayirmani oxirgi raqamini toping. A) 0 B) 2 C) 4 D) 6 29. yig’indini oxirgi raqamini toping. A) 0 B) 5 C) 4 D) 6 Download 12.73 Kb. Do'stlaringiz bilan baham: |
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