Mavzu: Eritmalar

Toshkent davlat pedagogika universiteti
Fizika-astranomiya yo’nalishi 101-guruh talabasi Davlatova Maxliyoning kimyo fanidan ishlagan masalalari.

MAVZU:Eritmalar

ERITMALAR
MASALALAR VA YECHIMLARI:
1.Ma’lum bir tuzning to’yingan eritmasining foiz konsen-tratsiyasi 40 bo’lsa,shu haroratdagi tuzning eruvchanlik konsentratsiyasini toping?
1)100g----100 60------40g X-------------40% 100-----X X=40g X=66,67g
2)100-40=60g
Javob:eruvchanlik konsentratsiyasi 66.67g.

2.KCl 20⁰C to’yingan eritmasining foiz konsentratsiyasi 25,37 bo’lsa,KCl ning shu haroratdagi eruvchanlik koeffitsientini toping?

100 0,2537=25,37g 100-25,37=74,63g 74,63-------25,37 100----------X X=33,99 Javob:Eruvchanlik koeffitsienti 33,99
3.KBr 40⁰C da to’yingan 200g eritmasini 30⁰C gacha sovutganda cho’kmaga tushadigan tuz massasini toping?
S₄₀=75,5; S₃₀=70,6
75,5-70,6=4,9 cho’kma
100+75,5=175,5 175,5---------4,9 cho’kma bo’lsa
200g---------x
X=5,58 Javob:Tuzning massasi 5,58g

4.KNO₃ 50⁰C da to’yingan 300g eritmasini 30⁰C gacha sovutganda cho’kmaga tushadigan tuz massasini toping?

S₅₀=85,5 S₃₀=45,8
85,5-45,8=39,7 cho’kma 100+85,5=185,5
185,5--------39,7 cho’kma bo’lsa 300---------x
x=64,2 Javob:Tuzning massasi 64,2g

5.Na₂SO₄ to’yingan eritmasidan ma’lum haroratdagi molyar konsentratsiyasi 1,2M bo’lsa shu haroratdagi tuzning eruvchanlik koeffitsientini toping?

1)n=C_H V=1,2 1=1,2 2)m_Na2SO4=1,2 142=170,4
1000-------170,4 100---------X
X=17,04 Javob:Eruvchanlik koeffitsienti 17,04

6.To’yingan eritmadan 200g suv bug’lanishi natijasida 80g kristallogidrat cho’kmaga tushdi.Kristallogidrat tarkibidagi tuzning massa ulushi(w%)ini toping?

100+25=125g
125---------25 280--------X x=56g w= Javob:tuzning massa ulushi 70%
7.Na₂SO₄ ma’lum haroratdagi to’yingan eritmasining eruvchanlik koeffitsientini 35,5 ga teng bo’lsa,shu haroratdagi eritmaning molyar va normal konsentrat-siyasini toping?
1) 1000--------X m_Na2SO4=142 X=355 100---------35,5 X=2,5 X=355 2)C_N= = =5
3) n=C_H V=2,5 1=2,5mol
1----------142 2,5--------X X=355 Javob:Molyar konsentratsiyasi 5,Normal konsentratsiyasi 2,5 mol

8.NaCl to’yingan eritmasidagi xlor va O₂ atomlari soni nisbati 1:10 bo’lsa,shu haroratdagi NaCl eruvchanlik koeffitsientini toping?

NaCl H₂O
;
180--------58,5 100--------X X=32,5 Javob:Eruvchanlik koeffitsienti 32,5

9.150g 40% li NaCl eritmasini hosil qilish uchun 50% li va 20% li eritmalardan necha grammdan olish kerak?

50% 20%
40%
20% 10%
50% 20% 40% 20g 10g 30g
150
y=100g x=50g
Javob: Eritmalardan 100g va 50g dan olish kerak

10.150g NaCl eritmasiga 50% li 300g shu tuz eritmasidan qo’shilganda 20% li eritma hosil bo’ldi.Dastlabki eritma konsentratsiyasini toping?

W= 100% 0,4=
150x+150=60+120
150x=30
X=0,2 100%
X=20%
Javob:Eritma konsentratsiyasi 20%