Mavzu: Tekis mexanizmlar uchun tezlanishlarm rejasini qurish

Mavzu: Tekis mexanizmlar uchun tezlanishlarm rejasini qurish.
Krivoship polzunli mexanizm uchun tezlanishlar rejasini qurish:
“OA” krivoship “O” nuqta atrofida bir tekis aylanma harakat qilmoqda;
_A= ⁿ_A + ^τ_A a^τ_A = 0
aⁿ_A= ω²_OA OA ω_OA=π×n1=3,14×1500 =157 rad/sek Tezlanishlar masshtabini aniqlaymiz:
aⁿ_A = ω² l_OA =157² 0,055=1355.69 m/s²
µ_a = aⁿ_A 50 =1355.69 50=27.11 (m/s²)/mm Shatun “AB” tekis-parallel harakat qilmoqda“A” nuqta qutb deb olindi:
_B = _A + _{AB B}= ⁿ_A+ ⁿ_AB + ^τ_BA Bu tenglamada hamma vektorlarning yo’nalishi ma’lum:
ⁿ_B // x-x
ⁿ_A “A” nuqtadan “O” nuqtaga yo’nalgan;
ⁿ_AB “BA” shatun bo’ylab “B” nuqtaga yo’nalgan;
^τ_BA “BA” shatunga tik yo’nalgan, lekin qaysi tomonga noma’lum;
aⁿ_A = ω² l_OA =157²×0,055=1355.69 m/s²
πa= 50 mm;
“a” nuqtadan “AB” ga tik chiziq o’tqazamiz;
“π” nuqtadan “x-x” ga parallel chiziq o’tqazamiz;

Barcha nuqtalardagi tezlanishlarni topamiz:

45 :
aⁿ_BA =ω²_AB l_AB=50,27² 0,13=328,5 m/s²
a-aⁿ = aⁿ_BA µ_a =328,5 27,11=12,11 mm
a^τ_BA=ab µ_a =27,11 30=813,3 m/s²
a_BA= ab µ_a =27,11×34=921,74 m/s²
a_B = b µ_a=27,11 40=1084,4m/s²
ɛ_AB = a^τ_BA l_AB =813,3 0,13=6256,1 s²
90°:
aⁿ_BA =ω²_AB l_AB=0 m/s²
a-aⁿ = aⁿ_BA µ_a =0
a^τ_BA=ab µ_a =60×27,11=1626 m/s²
a_BA= ob µ_a =60 27,11=1626m/s²
a_B = b µ_a =40 27,11=1084 m/s²
ɛ_AB = a^τ_BA l_AB =1626÷0,13=12507 s²
135°:
aⁿ_BA =ω²_AB l_AB=50,27²×0,13=328,5m/s²
a-aⁿ = aⁿ_BA µ_a =328,5÷27,11=12,11 mm
a^τ_BA=ab µ_a =38 27,11 =1030 m/s²
a_BA= ob µ_a =27,11 48 =1301,2 m/s²
a_B = b µ_a =50 27,11=135550 m/s²
ɛ_AB = a^τ_BA l_AB =1030 0,13=79,23 s^-2
180°:
aⁿ_BA=ω²_AB l_AB=66,15² 0,13=568,85 m/s²
a-aⁿ = aⁿ_BA µ_a =568,85 27,11=20,9 mm
a^τ_BA=ab µ_a =0
a_BA= ob µ_a =0
a_B = b µ_a = 50 27,11 =1355 m/s²
ɛ_AB = a^τ_BA l_AB = 0
225°:
aⁿ_BA =ω²_AB l_AB=(47,6)² 0,13=294,5 m/s²
a-aⁿ = aⁿ_BA µ_a =294,4 27,11 =10,86 mm
a^τ_BA=ab µa=50 27,11 =22,89 m/s²
a_BA= ob µ_a =20 27,11=542,2 m/s²
a_B = b µ_a =70 27,11 =1897,7 m/s²
ɛ_AB = a^τ_BA l_AB =22,89 0,13 =176 s²
270°:
aⁿ_BA =ω²_AB l_AB= 0
a-aⁿ = aⁿ_BA µ_a =0
a^τ_BA=ab µ_a =60×27,11=1626,6 m/s²
a_BA= ob µ_a =60 27,11 =1,626 m/s²
a_B = b µ_a = 20 27,11=542,2 m/s²
ɛ_AB = a^τ_BA l_AB =1626÷0,13=12507 s²
315°:
aⁿ_BA =ω²_AB l_AB=50² 0,13=325 m/s²
a-aⁿ = aⁿ_BA µ_a =325 27,11=11,9 mm
a^τ_BA= ab µ_a =34 27,11=921 m/s²
a_BA= ob µ_a =33 27,11 =894,63 m/s²
a_B = b µ_a =35 27,11=948,8 m/s²
ɛ_AB = a^τ_BA l_AB =921 0,13=7084 s²
360°:
aⁿ_BA=ω²_AB l_AB=66,15² 0,13=568,8 m/s²
a-aⁿ = aⁿ_BA µ_a =568,8÷27,11=20,9 mm
a^τ_BA=ab µ_a =0
a_BA= ob µ_a = 0
a_B = b µ_a = 50 27,11=1355 m/s²
ɛ_AB = a^τ_BA l_AB = 0