Project Management in the Oil and Gas Industry
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2.Project management in the oil and gas industry 2016
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- Figure 2.22
Dry
No drill Drill Figure 2.20 Case study one. 0.8 0.5 0.5 0.1 0.01 110 1.1 3.0 0.6 0.4 1.2 0.3 –4.8 50 20 40 20 10 –6 0.06 0.03 0.01 0.06 0.03 0.80 1.0 1.8 1 2 3 4 5 6 7 0.6 0.3 0.1 0.6 0.3 No delay Delay 2 years 0.2 Dry P PV = EPV Figure 2.21 Case study two. 74 Project Management in the Oil and Gas Industry that permit administrative bureaucracy where the delay is a result of administrative work for foreign permits and correspondence papers or for the equipment for customs paper work. This is an example where the auger is not available and this is something that will have an impact on the accounts of the present value of investment, as in the following exam- ple. It is clear that the number of decision-making trees depends primar- ily on the experience, as it considers all the possible problems that can be urged as well as prospects. Figure 2.22 presents another example for constructing a new facil- ity and you may cancel this project or go through the appraise phase (conceptual design). The possible outcomes from the study are that you will need a plant or not. Due to production, there are three possible outcomes: abandon the facility, make no modifications, or modify the facility. The decision tree is very easy to use, but the problem is how to calculate the probability for every event. You can assume the probability value using your experience, but it will affect the result. The most proper way to calculate this probability is by using the Monte- Carlo simulation technique. In every case, start by building a model for a reservoir in an oil and gas project, and define the mean, standard deviation, and the probability distribution that are present in the reservoir model, such as area, height, porosity and others parameters. At the same time, build the model for the present value calculation and define the parameters for each variable. 1 2 3 4 5 0.47 238 = 111.8 0.11 140 = 15.4 0.14 10 = 1.4 0.08 –113 = –9.0 0.02 –31 = –6.2 1.00 113.4 t t + 3 t + 7 t + 15 Cancel project No plant Construct initial facility Appraise phase 0.20 0.80 0.90 0.10 0.65 0.15 0.20 Modify facility Abandon facility No modification P PV = EPV Figure 2.22 Case study three. |
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