Answer: 2019+(71-0.5)/(365+0)=2019.193;
2013+(97-0.5)/(365+0)=2013.264;
2012+(143-0.5)/(365+1)=2012.390;
Discretization
I
|
D
|
D_d
|
100
|
2000.000
|
D1
|
101
|
2003.120
|
D1
|
102
|
2011.144
|
D3
|
103
|
2005.333
|
D2
|
104
|
2001.108
|
D1
|
105
|
2013.975
|
D3
|
106
|
2020.000
|
D4
|
107
|
2017.455
|
D4
|
108
|
2012.143
|
D3
|
109
|
2018.555
|
D4
|
110
|
2007.005
|
D2
|
Answer:
To discretize the D attribute into 4 bins(consecutive intervals), we use this formula
here, is the number of bins, are min and max gradations of the attribute. So ;
s; ;
;
now we put D attribute elements into bins, if it is in the first interval we put D_d column D1…
Bins
|
D_d
|
[2000.000 , 2005.000]
|
D1
|
(2005.000 , 2010.000]
|
D2
|
(2010.000 , 2015.000]
|
D3
|
(2015.000 , 2020.000]
|
D4
|
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