Savollariga javoblar
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31298 answer geometriya sessiya oraliq javob-2
GEOMETRIYA FANIDAN SESSIYA ORALIQ
SAVOLLARIGA JAVOBLAR
YO’NALISH: MATEMATIKA VA INFORMATIKA
GURUH:103
Topshiruvchi:Mamatkarimov Shaxzod
7-variant 89)Uchburchakning uchlari berilgan: A(0; 1) , B(6; 5) va C(12; -1). C uchidan tushurilgan uchburchak balandlik tenglamasini tuzing. Javob:
B(6; 5)
A(0, 1) C(12;-1) AB=B-A=(6; 5) – (0; 1) = (6; 4) BC=C-B=(12; -1) – ( 6; 5) =(6;-6) AC=C-A=(12;-1) – (0; 1) = (12;-2) AB tomon uzunligi: √(6²+4²) =√(52)=2√(13) BC tomon uzunligi:√(6²+(-6)²)=√(72)=6√2 AC tomon uzunligi :√(12)²+(2)²=√(148)=2√(37) Demak:
2√37 S2=½ *c*h
S1=S2 ½*c*h=
H= √((√(13)+3√2+√(37))*(√(13)+3√2-√(37))*(√(13)+√(37)- 3√2)*(√(13)+√(37)-3√2)) √(13)*h=√(936-36) √(13)*h=30 H=30*√(13)/13 JAVOB. H=30*√(13)/13
25) L(0; 0), M(3; 0). N(0; 4) nuqtalar uchburchak tomonlari o'rtalarining koordinatalari. Uchburchak yuzasini hisoblang. B(3, 4)
M N
A (3,-4) L C(-3,4) 1-usul:Uchburchak uchlarining koordinatalari bo'yicha ularning yuzini hisoblash formulasi orqali hisoblaymiz. FORMULA→S=½*|x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)|S= ½*|3*(4- 4)+3*(4-(-4))+(-3)*(-4-4)|=½*|0+3*8+3*8|=½*48=24 A
√( p
x (p-a)*(p-b)*(p-c)
S1=
C
√( p x (p-a)*(p-b)*(p-c) 2√(37)
134) 1) x² + y² - 8x +6y =0; 2) x²+y²+ 10x-4y +29=0; 3) x² +y²- 4x +14y +54=0 aylanalarning radiusi va markazi koordinatalarini toping. 1.x² + y² - 8x +6y =0 2. x²+y²+ 10x-4y +29=0 x²-8x+16+y²+6y+9=25 x²+10x+25+y²-4y+4-29+29=0 (x-4)²+(y+3)²=5² (x+5)²+(y-2)²=0 Aylana radiusi→5 Aylana radiusi→0 Markazi koordinatalari→(4,5) Markazi kordinatalari→(-5, 2)
3.x² +y²- 4x +14y +54=0 X²-4x+4+y²+14y+49-53+54=0 (x-2)²+(y+7)²=-1 Aylana tenglamasi noto'g'ri.
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