Sets for an overlapping sets problem it is best to use a double set matrix to organize the information and solve. Fill in the information in the order in which it is given


Obviously, 20%men+10%women>10%(men+women). Answer is B 43


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GMAT Quant Topic 1 (General Arithmetic) Solutions

42.
Obviously, 20%men+10%women>10%(men+women).
Answer is B


43.
We know that: revenue=gross profit + expense
1). Revenue=1/3 expense+expense=4/3 expense, gross profit is 1/4 of its revenue.
2). Gross profit=revenue ¨Cexpense=1/4 revenue, gross profit is 1/4 of its revenue.
Answer is D

44.
1). The discount of the most expensive item was 20%*50=$10, the discount of the next expensive item was 10%*20=2


let the regular price of the other item is x, then x<=20 and discount is 10%x
So, total discount is 10+2+0.1X, sum of the regular price is 50+20+X
Then, total discount/sum of the regular prices was:
(12+0.1x)/(70+x)=(7+0.1X+5)/(70+x)=0.1+5/(70+x)
We know that 0Then, (12+0.1x)/(70+X)>=0.1+1/18=7/45>0.15
2) is insufficient.
Answer is D
45.
Rate = A^2/B, the question asks how shall A change to cope with a 100% increase of B to make the rate constant.
(xA)^2/(2B) = A^2/B => x^2=2 => x=1.414 => A has to increase to 1.414A, equivalent to say an increase of approximate 40%


46.
let y=x, the number of people working more than 10 years=560
(560-x)/(800-x)=60%=>x=200


47.
2%A+(100+1%A)/2=50+A/40


48.
Let the least one is x. When other 10 populations have the greatest value, x will have the minimum value.
X+10*1.1X=132000
X=11000
Answer is D


49.
Let the price at the beginning is 1, then at the end of the first quarter, it was 1.2, at the end of the second quarter, it was 1.5.
(1.5-1.2)/1.2=25%
Answer is B

50.
(150+profit)*40%=profit


So, the profit is $100

51.
The profit is sale price-cost


For one stock, (sale price-cost)/cost=20%, its cost is 96/1.2=80
For the other stock, (sale price-cost)/cost=-20%, cost is 96/0.8=120
Then, the total profit for the two stocks is:
96-80+96-120=-8
Answer is C

52.
60%*120%/(40%+60%*120%)=64%


53.
Amy was the 90th percentile of the 80 grades for her class, therefore, 10% are higher than Amy's, 10%*80=8.


19 of the other class was higher than Amy. Totally, 8+19=27
Then, the percentile is:
(180-27)/180=85/100
Answer is D



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