Son va raqamlar


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Dasturlash I 2-mustaqil ish


1. ( Son va raqamlar ). Uch xonali sonning raqamlarini o’sish tartibida joylashtiring .
#include

using namespace std;


int main()


{
int n, a, b, c, result;
cout<<"Uch xonali son kiriting:";cin>>n;
a = n % 10; n = n / 10;
b = n % 10; n = n / 10;
c = n % 10;
cout<<"sonlar o'sish tartibida:";
if(a>b & a>c){
if(b>c){
cout<}
else
cout<} else if(b>a & b>c){
if(a>c){
cout<}
else
cout<} else if(c>b & c>a){
if(b>a){
cout<}
else
cout<}

return 0;


}

2. ( Nuqta va doira ) N nuqtaning koordinatalari(x,y) va doira radiusi(R) kiritadi. Bunda doiraning markazi koordinata o’qining boshida yotadi. Nuqta doiraning ichida yotadimi


#include
#include

using namespace std;


float distance(int x1, int y1, int x2, int y2)


{
return sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2) * 1.0);
}

int main()


{
float m, R;
int x1, y1, c, x2 = 0, y2 = 0;
cout<<"Quyidagi tartibda kiriting: X1, y1, R:";cin>>x1>>y1>>R;
if(distance(x1,y1,x2,y2) < R)
cout<<"Nuqta doira ichida"<else if(distance(x1,y1,x2,y2) > R)
cout<<"Nuqta doiradan tashqarida";
else
cout<<"Nuqta doira chegarasida";
return 0;
}

3. (Tub bo’luvchilar). Berilgan natural sonning barcha tub bo‘luvchilari chop etilsin.


#include


#include

using namespace std;


float distance(int x1, int y1, int x2, int y2)


{
return sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2) * 1.0);
}

int main()


{
float m, R;
int x1, y1, c, x2 = 0, y2 = 0;
cout<<"Quyidagi tartibda kiriting: X1, y1, R:";cin>>x1>>y1>>R;
if(distance(x1,y1,x2,y2) < R)
cout<<"Nuqta doira ichida"<else if(distance(x1,y1,x2,y2) > R)
cout<<"Nuqta doiradan tashqarida";
else
cout<<"Nuqta doira chegarasida";
return 0;
}

4. 3 ta butun son berilgan bu sonlar arifmetik progressiyaning hadlari bo’la oladimi ?


#include
using namespace std;

int main()


{
int a,b,c,m;cin>>a>>b>>c;
m = b-a;
m = b+m;
if(c = m){
cout << "Ha";
}
else{
cout << "yo'q";
}
return 0;
}

5. tezlanish bilan harakatini boshlagan jism t vaqtdan so’ng qancha masofani bosib o’tadi .


#include
using namespace std;

int main()


{
int a,t; cin>>a>>t;
cout<<((a*t*t)/2);
return 0;
}

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