Taasggatss a 20 b 22 c 24 d 25 Ishlanishi
A) 42 B) 84 C) 21 D) 168 Ishlanishi
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A) 42 B) 84 C) 21 D) 168 Ishlanishi: 1) L=N*0,34 => N=L/0,34 N=42,84nm/0,34nm=126N 2) i-RNK 126 ta nukleotid bo’ladi. Shunga ko’ra, bu nukleotidlar nechta aminokislotani kodlashini topamiz : AK=N/3 AK=126N/3=42AK Javob: A ____________________________ 72. DNK molekulasining uzunligi 42,84 nm bo’lsa, shu molekulasidagi nukleotidlar sonini toping. A) 126 B) 252 C) 504 D) 63
1) L=N*0,34 => N=L/0,34 N=42,84nm/0,34nm=126N 2) i-RNK 126 ta nukleotid, DNK da 2 ta zanjirda : 126*2=252N Javob: B ____________________________ 73. DNK molekulasining uzunligi 42,84 nm bo’lsa, shu molekula asosida sintezlangan oqsilning og’irligini toping. 1 dona aminokislotaning o’rtacha og’irligi 120 D. A) 5040 B) 10080 C) 2520 D) 20160
1) L=N*0,34 => N=L/0,34 N=42,84nm/0,34nm=126N 2) i-RNK 126 ta nukleotid bo’ladi. Shunga ko’ra, bu nukleotidlar nechta aminokislotani kodlashini topamiz : AK=N/3 AK=126N/3=42AK 3) M=AK*120 M=42*120=5040D Javob: A ____________________________ 74. DNK molekulasining uzunligi 42,84 nm bo’lsa, shu molekula tarkibidagi fosfodiefir bog’lari sonini aniqlang. A) 124 B) 125 C) 250 D) 251 Ishlanishi: 1) L=N*0,34 => N=L/0,34 N=42,84nm/0,34nm=126N 2) i-RNK 126 ta nukleotid, DNK da 2 ta zanjirda : 126*2=252N 3) F=N-2 F=252-2=250 Javob: C ____________________________ 75. DNK molekulasining uzunligi 42,84 nm. Shu DNK mutatsiyaga uchrab 6 juft nukleotidini yo’qotdi. Ushbu molekula asosida sintezlangan oqsil tarkibidagi aminokislotalar sonini aniqlang. A) 40 B) 38 C) 42 D) 36 Ishlanishi: 1) L=N*0,34 => N=L/0,34 N=42,84nm/0,34nm=126N 2) i-RNK 126 ta nukleotid bo’ladi. 126-6=120N Shunga ko’ra, bu nukleotidlar nechta aminokislotani kodlashini topamiz : 3) AK=N/3 AK=120N/3=40AK Javob: A ____________________________ 76. DNK molekulasining uzunligi 42,84 nm. Shu DNK mutatsiyaga uchrab 12 juft nukleotidini yo’qotdi. Ushbu molekula asosida sintezlangan oqsil tarkibidagi aminokislotalar sonini aniqlang. A) 40 B) 38 C) 36 D) 34
1) L=N*0,34 => N=L/0,34 N=42,84nm/0,34nm=126N 2) i-RNK 126 ta nukleotid bo’ladi. 126-12=114N Shunga ko’ra, bu nukleotidlar nechta aminokislotani kodlashini topamiz : 3) AK=N/3 AK=114N/3=38AK Javob: B ____________________________ 77. Nuklein kislotalar molekulasida nukleotidlar o'zaro fosfodiefir bog'lari orqali bog'lanadi. DNK molekulasida 598 ta fosfodiefir bog‘i bo‘lsa va undagi adenin nukleotidi umumiy nukleotidlarni 20% tashkil etsa, ushbu DNK molekulasidagi guanin va uratsil nukleotidlarini sonini aniqlang? A) 120;180 B) 180;120 C) 118;0 D) 180;0 Ishlanishi: 1) 598+2=600N DNK dagi barcha N lar 2) 600---100% x---20% x=(600*20)/100=120 A=120 3) 600---100% x---30% x=(600*30)/100=180 G=180 ; U=0 Javob: D ____________________________ 78. Translyatsiyada hosil bo’lgan oqsil 400 ta aminokislotaga ega bo’lsa, shu oqsil haqida axborot saqlovchi DNK dagi nukleotidlar sonini aniqlang. A) 1200 B) 2400 C) 600 D) 1800
1) N=AK*3 N=400*3=1200 i-RNK yoki DNK ning bitta zanjiridagi N lar 2) 1200*2=2400N Javob: B ____________________________ 79. 46080 D og’irlikdagi oqsil sinteziga javobgar DNK tarkibidagi fosfodiefir bog’lar sonini toping. A) 1152 B) 2304 C) 1150 D) 2302 Ishlanishi: 1) 46080/120=384AK 2) N=AK*3 N=384*3=1152N –bu i-RNK dagi yoki DNK ning sintezlangan zanjiridagi N lar 3) 1152*2=2304N –bu 2 ta zanjirdagi N lar 4) F=N-2 F=2304-2=2302 2302 Javob: D ____________________________ 80. Ma’lum bir oqsil bo’lagida 41 ta peptid bog’ mavjud. Shu oqsil haqida axborot saqlovchi DNK dagi 3-6-7 juft nukleotidlar deletsiyaga uchradi. Shundan so’ng hosil bo’lgan oqsildagi aminokislotalar sonini aniqlang.
1) 41+1=42AK 2) N=AK*3 N=42*3=126N –bu i-RNK dagi yoki DNK ning sintezlangan zanjiridagi N lar 3) Lekin 3 juft N deletsiyaga uchragan (yo’qolgan): 126-3=123 4) AK=N/3 AK=123/3=41 Javob: A ____________________________ 81. Ma’lum bir oqsil bo’lagida 41 ta peptid bog’ mavjud. Shu oqsil haqida axborot saqlovchi DNK dagi 3-6-7 juft nukleotidlar inversiyaga uchradi. Shundan so’ng hosil bo’lgan oqsildagi aminokislotalar sonini aniqlang. A) 41 B) 42 C) 40 D) 43 Ishlanishi: 1) 41+1=42AK 2) N=AK*3 N=42*3=126N –bu i-RNK dagi yoki DNK ning sintezlangan zanjiridagi N lar 3) Lekin 3 juft N inversiyaga uchragan (o‘z o‘rnini 180° ga o‘zgartirgan): 126 ta N lar soni o’zgarmagan 4) AK=N/3 AK=126/3=42 Javob: B ____________________________ 82. Ma’lum bir oqsil bo’lagida 41 ta peptid bog’ mavjud. Shu oqsil haqida axborot saqlovchi DNK dagi 3-6-7 juft nukleotidlar duplikatsiyaga uchradi. Shundan so’ng hosil bo’lgan oqsildagi aminokislotalar sonini aniqlang. A) 41 B) 42 C) 40 D) 43
1) 41+1=42AK 2) N=AK*3 N=42*3=126N –bu i-RNK dagi yoki DNK ning sintezlangan zanjiridagi N lar 3) Lekin 3 juft N duplikatsiyaga uchragan (ortgan): 126+3=129 4) AK=N/3 AK=129/3=43 Javob: A ____________________________ 83. Ma’lum bir oqsil bo’lagida 37 ta peptid bog’ mavjud. Shu oqsil haqida axborot saqlovchi DNK dagi 2-6-9 juft nukleotidlar deletsiyaga uchradi. Shundan so’ng hosil bo’lgan oqsildagi aminokislotalar sonini aniqlang. A) 36 B) 37 C) 38 D) 39 Ishlanishi: 1) 37+1=38AK 2) N=AK*3 N=38*3=114N –bu i-RNK dagi yoki DNK ning sintezlangan zanjiridagi N lar 3) Lekin 3 juft N deletsiyaga uchragan (yo’qolgan): 114-3=111 4) AK=N/3 AK=111/3=37 Javob: B ____________________________ 84. Ma’lum bir oqsil bo’lagida 37 ta peptid bog’ mavjud. Shu oqsil haqida axborot saqlovchi DNK dagi 2-6-9 juft nukleotidlar inversiyaga uchradi. Shundan so’ng hosil bo’lgan oqsildagi aminokislotalar sonini aniqlang. A) 36 B) 37 C) 38 D) 39 Ishlanishi: 1) 37+1=38AK 2) N=AK*3 N=38*3=114N –bu i-RNK dagi yoki DNK ning sintezlangan zanjiridagi N lar 3) Lekin 3 juft N inversiyaga uchragan (o‘z o‘rnini 180° ga o‘zgartirgan): 114 ta N lar soni o’zgarmagan 4) AK=N/3 AK=114/3=38 Javob: C ____________________________ 85. Ma’lum bir oqsil bo’lagida 37 ta peptid bog’ mavjud. Shu oqsil haqida axborot saqlovchi DNK dagi 2-6-9 juft nukleotidlar duplikatsiyaga uchradi. Shundan so’ng hosil bo’lgan oqsildagi aminokislotalar sonini aniqlang. A) 36 B) 37 C) 38 D) 39
1) 37+1=38AK 2) N=AK*3 N=38*3=114N –bu i-RNK dagi yoki DNK ning sintezlangan zanjiridagi N lar 3) Lekin 3 juft N duplikatsiyaga uchragan (ortgan): 114+3=117 4) AK=N/3 AK=117/3=39 Javob: D ____________________________ 86. i-RNK da U-19% va A-25% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjirida T-necha % ni tashkil qiladi.
A)22% B)24% C)44% D)25% Ishlanishi: 1) DNK dagi T ni topish: i-RNK dagi T=(U+A)/2 T=(19%+25%)/2=22% Javob: A ____________________________ 87. i-RNK da S-19% va G-25% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjirida S-necha % ni tashkil qiladi.
1) DNK dagi S ni topish: i-RNK dagi T=(G+S)/2 T=(19%+25%)/2=22% Javob: A ____________________________ 88. i-RNK da U-19%, S-11% va A-25% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjiridagi fosfodiefir bog`lar sonini aniqlang.
1) U-19%, S-11%, A-25%, G-? G=100-(U+S+A)=45% 2) DNK ning 1 ta ipidagi N larni topamiz: N= U+S+A+G N=19+11+25+45=100 3) 100*2=200 F=200-2=198 Javob: A ____________________________ 89. i-RNK da U-19%, S-11% va A-25% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjiridagi vodorod bog`lar sonini aniqlang.
1) G=100-(U+S+A)=45% 2) DNK ning 1 ta ipidagi N larni topamiz: N= U+S+A+G DNK dagi S ni topish: i-RNK dagi T=(G+S)/2 N=(U)19+(S)11+(A)25+(G)45=100 3) A-
T=(19+25)=44 G-S=(11+45)=56 4) H=2A+3G H=(2*44)+(3*56)=88+168=256 Javob: A ____________________________ 90. i-RNK da U-19%, S-11% va A-25% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjiridagi S va G lar orasidagi vodorod bog`lar sonini aniqlang. A)198 B)168 C)98 D)188 Ishlanishi: 1) G=100-(U+S+A)=45% 2) DNK ning 1 ta ipidagi N larni topamiz: N= U+S+A+G DNK dagi S ni topish: i-RNK dagi T=(G+S)/2 N=(U)19+(S)11+(A)25+(G)45=100
3) A- T=(19+25)=44 G-S=(11+45)=56 4) H=3G H=3*56=168 Javob: B ____________________________ 91. i-RNK da U-19%, S-11% va A-25% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjiridagi A va T lar orasidagi vodorod bog`lar sonini aniqlang. A)78 B)108 C) 88 D)98
1) G=100-(U+S+A)=45% 2) DNK ning 1 ta ipidagi N larni topamiz: N= U+S+A+G DNK dagi S ni topish: i-RNK dagi T=(G+S)/2 N=(U)19+(S)11+(A)25+(G)45=100 3) A-
T=(19+25)=44 G-S=(11+45)=56 4) H=2A H=2*44=88 Javob: C ____________________________ 92. i-RNK da U-19%, S-11% va A-25% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjirini uzunligini aniqlang.(nukleotidlar orasidagi masofa 0,34nm) A)51nm B)34nm C)68nm D)54,4nm Ishlanishi: 1) U-19%, S-11%, A-25%, G-? G=100-(U+S+A)=45% 2) DNK ning 1 ta ipidagi N larni topamiz: N= U+S+A+G N=19+11+25+45=100 3) L=N*0,34 L=100*0,34=34nm Javob: B ____________________________ 93.i-RNK da U-25% va A-15% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjiridagi T-% miqdorini aniqlang.
1) DNK dagi T ni topish: i-RNK dagi T=(U+A)/2 T=(25%+15%)/2=20% Javob: A ____________________________ 94. i-RNK da U-25%, G-30% va A-15% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjiridagi S-% miqdorini aniqlang. A)20% B)30% C)40% D)15% Ishlanishi: 1) U-25%, G-30%, A-15%, S-? S=100-(U+G+A)=30% 2) S=(G+S)/2 S=(30+30)/2=30% Javob: B ____________________________ 95. i-RNK da U-25% va A-15% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjiridagi vodorod bog`lar sonini aniqlang.
1) T=U+A T-A=25+15=40 2) 100-40=60 G-S=60 3) H=2A+3G H=(2*40)+(3*60)=80+180=260 Javob: A
____________________________ 96. i-RNK da U-25% va A-15% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjiridagi A va T orasidagi vodorod bog`lar sonini aniqlang.
1) T=U+A T-A=25+15=40 2) 100-40=60 G-S=60 3) H=2A H=2*40=80 Javob: A
____________________________ 97. i-RNK da U-25% va A-15% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjiridagi G va S orasidagi vodorod bog`lar sonini aniqlang.
1) T=U+A T-A=25+15=40 2) 100-40=60 G-S=60 3) H=3G H=3*60=180 Javob: A
____________________________ 98. i-RNK da U-25% va A-15% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjirini uzunligini aniqlang.(nukleotidlar orasidagi masofa 0,34nm)
1) T=U+A T-A=25+15=40 2) 100-40=60 G-S=60 3) DNK ning 1 ta ipidagi N lar topiladi : 40+60=100 4) L=N*0,34 L=100*0,34=34 Javob: A
____________________________ 99. i-RNK da U-25% va A-15% bo`lsa teskari transkripsiya jarayonida hosil bo`lgan DNK qo`sh zanjiridagi fosfodiefir bog`lar sonini aniqlang.
1) T=U+A T-A=25+15=40 2) 100-40=60 G-S=60 3) DNK ning 1 ta ipidagi N lar topiladi : 40+60=100 4) 100*2=200 F=200-2=198 Javob: A
____________________________ 100. Ma`lum sharoitda 105,4 nm uzunlikdagi DNK malekulasi BamHI restiriktaza fermenti ta`sirida ABCD bo`laklarga bo`lindi Hosil bo`lgan barcha DNK malekulasidagi vodorod bog`lar soni dastlabki vodorod bog`lar sonidan 3,75% ga kam bo`lsa dastlabki DNK malekulasidagi G-S orasidagi vodorod bog`lar sonini toping.
1) N=L/0,34 N=105,4/0,34=310 310*2=620 2) BamHI har bir kesgan joyda GATC orasidagi H bog’larni uzadi. 3+2+2+3=10 G-S=2*3=6 ta A-T=2*2=4 ta 3 joydan kesilgan va ABCD bo’laklarga bo’lingan: 10*3=30 3) 30---3,75% x---100% x=(30*100)/3,75=800 4) 2A+3G=800 2A+2G=620 G=180 2A+3*180=800 2A=360 A=130 5) H=3G H=3*180=540 Javob: A
____________________________ 101. Ma`lum sharoitda 105,4 nm uzunlikdagi DNK malekulasi BamHI restiriktaza fermenti ta`sirida ABCD bo`laklarga bo`lindi Hosil bo`lgan barcha DNK malekulasidagi vodorod bog`lar soni dastlabki vodorod bog`lar sonidan 3,75% ga kam bo`lsa dastlabki DNK malekulasidagi A-T orasidagi vodorod bog`lar sonini toping.
1) N=L/0,34 N=105,4/0,34=310 310*2=620 2) BamHI har bir kesgan joyda GATC orasidagi H bog’larni uzadi. 3+2+2+3=10 G-S=2*3=6 ta A-T=2*2=4 ta 3 joydan kesilgan va ABCD bo’laklarga bo’lingan: 10*3=30 3) 30---3,75% x---100% x=(30*100)/3,75=800 4) 2A+3G=800 2A+2G=620 G=180 2A+3*180=800 2A=360 A=130 5) H=2A H=2*130=260 Javob: A
____________________________ 102. Ma`lum sharoitda 105,4 nm uzunlikdagi DNK malekulasi BamHI restiriktaza fermenti ta`sirida ABCD bo`laklarga bo`lindi Hosil bo`lgan barcha DNK malekulasidagi vodorod bog`lar soni dastlabki vodorod bog`lar sonidan 3,75% ga kam bo`lsa hosil bo`lgan barcha DNK malekulasidagi A-T orasidagi vodorod bog`lar sonini toping. A)260 B)248 C)522 D)540
1) N=L/0,34 N=105,4/0,34=310 310*2=620 2) BamHI har bir kesgan joyda GATC orasidagi H bog’larni uzadi. 3+2+2+3=10 G-S=2*3=6 ta A-T=2*2=4 ta 3 joydan kesilgan va ABCD bo’laklarga bo’lingan: 10*3=30 3) 30---3,75% x---100% x=(30*100)/3,75=800 4) 2A+3G=800 2A+2G=620 G=180 2A+3*180=800 2A=360 A=130 5) H=2A H=2*130=260 260-12=248 Javob: B
____________________________ 103. Ma`lum sharoitda 110,5 nm uzunlikdagi DNK malekulasi Eco.RI restiriktaza fermenti ta`sirida ABC bo`lakka bo`lindi.Hosil bo`lgan barcha DNK malekulasidagi vodorod bog`lar soni dastlabki vodorod bog`lar sonidan 2% ga kam bo`lsa dastlabki DNK malekulasidagi G-S orasidagi vodorod bog`lar sonini toping.
1) N=L/0,34 N=110,5/0,34=325 325*2=650 2) Eco.RI har bir kesgan joyda AATT orasidagi H bog’larni uzadi. 2+2+2+2=10 A-T=2*4=8 ta 2 joydan kesilgan va ABC bo’laklarga bo’lingan: 8*2=16 3) 16---2% x---100% x=(30*100)/2=800 4) 2A+3G=800 2A+2G=650 G=150 2A+3*150=800 2A=350 A=175 5) H=3G H=3*150=450 Javob: A
____________________________ 104. Ma`lum sharoitda 110,5 nm uzunlikdagi DNK malekulasi Eco.RI restiriktaza fermenti ta`sirida ABC bo`lakka bo`lindi.Hosil bo`lgan barcha DNK malekulasidagi vodorod bog`lar soni dastlabki vodorod bog`lar sonidan 2% ga kam bo`lsa dastlabki DNK malekulasidagi A-T orasidagi vodorod bog`lar sonini toping. A)450 B)350 C)334 D)434 Ishlanishi: 1) N=L/0,34 N=110,5/0,34=325 325*2=650 2) Eco.RI har bir kesgan joyda AATT orasidagi H bog’larni uzadi. 2+2+2+2=10 A-T=2*4=8 ta 2 joydan kesilgan va ABC bo’laklarga bo’lingan: 8*2=16 3) 16---2% x---100% x=(16*100)/2=800 4) 2A+3G=800 2A+2G=650 G=150 2A+3*150=800 2A=350 A=175 5) H=2A H=2*175=350 Javob: B
____________________________ 105. Ma`lum sharoitda 110,5 nm uzunlikdagi DNK malekulasi Eco.RI restiriktaza fermenti ta`sirida ABC bo`lakka bo`lindi.Hosil bo`lgan barcha DNK malekulasidagi vodorod bog`lar soni dastlabki vodorod bog`lar sonidan 2% ga kam bo`lsa hosil bo`lgan DNK malekulasidagi G-S orasidagi vodorod bog`lar sonini toping.
1) N=L/0,34 N=110,5/0,34=325 325*2=650 2) Eco.RI har bir kesgan joyda AATT orasidagi H bog’larni uzadi. 2+2+2+2=10 A-T=2*4=8 ta 2 joydan kesilgan va ABC bo’laklarga bo’lingan: 8*2=16 3) 16---2% x---100% x=(16*100)/2=800 4) 2A+3G=800 2A+2G=650 G=150 2A+3*150=800 2A=350 A=175 5) H=3G H=3*150=450 Javob: A
____________________________ 106. Ma`lum sharoitda 110,5 nm uzunlikdagi DNK malekulasi Eco.RI restiriktaza fermenti ta`sirida ABC bo`lakka bo`lindi.Hosil bo`lgan barcha DNK malekulasidagi vodorod bog`lar soni dastlabki vodorod bog`lar sonidan 2% ga kam bo`lsa hosil bo`lgan DNK malekulasidagi A-T orasidagi vodorod bog`lar sonini toping. A)450 B)350 C)334 D)434 Ishlanishi: 1) N=L/0,34 N=110,5/0,34=325 325*2=650 2) Eco.RI har bir kesgan joyda AATT orasidagi H bog’larni uzadi. 2+2+2+2=10 A-T=2*4=8 ta 2 joydan kesilgan va ABC bo’laklarga bo’lingan: 8*2=16 3) 16---2% x---100% x=(16*100)/2=800 4) 2A+3G=800 2A+2G=650 G=150 2A+3*150=800 2A=350 A=175 5) H=2A H=2*175=350 350-16=334 Javob: C
____________________________ 107. Ma`lum sharoitda 81,6 nm uzunlikdagi DNK malekulasi BamHI restiriktaza fermenti ta`sirida ABCD bo`laklarga bo`lindi Hosil bo`lgan barcha DNK malekulasidagi vodorod bog`lar soni dastlabki vodorod bog`lar sonidan 5% ga kam bo`lsa dastlabki DNK malekulasidagi G-S orasidagi vodorod bog`lar sonini toping.
1) N=L/0,34 N=81,6/0,34=240 240*2=480 2) BamHI har bir kesgan joyda GATC orasidagi H bog’larni uzadi. 3+2+2+3=10 G-S=2*3=6 ta A-T=2*2=4 ta 3 joydan kesilgan va ABCD bo’laklarga bo’lingan: 10*3=30 3) 30---5% x---100% x=(30*100)/5=600 4) 2A+3G=600 2A+2G=480 G=120 2A+3*120=600 2A=240 A=120 5) H=3G H=3*120=360 Javob: A
____________________________ 108. Ma`lum sharoitda 81,6 nm uzunlikdagi DNK malekulasi BamHI restiriktaza fermenti ta`sirida ABCD bo`laklarga bo`lindi Hosil bo`lgan barcha DNK malekulasidagi vodorod bog`lar soni dastlabki vodorod bog`lar sonidan 5% ga kam bo`lsa dastlabki DNK malekulasidagi A-T orasidagi vodorod bog`lar sonini toping. A)360 B)240 C)228 D)342 Download 0.58 Mb. Do'stlaringiz bilan baham: 
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