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4 Metodichka 2011


3A (3,3)R

2. Simmetriklik sharti: (x, y)R(y, x)R;

(1,2)R (2,1)R;

(2,1)R (1,2)R.

3. Tranzitivlik sharti: (x, y)R, (y,z)R (x,z)R.

(2,1)R , (1,2)R (2,2)R

(1,2)R , (2,1)R (1,1)R

Demak A={1, 2, 3} to‘plamning dekart kvadratida aniqlangan R={(1,1), (2,2), (3,3), (1,2), (2,1)} munosabat ekvivalent munosabat bo‘ladi.



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