ά1 = 12835.8 Vt/m² K ga teng
Yuqoridagi xisoblardan foydalanib endi aynan shu uskunaning issiqlik uzatish koeffitsenti kus - ni aniqlaymiz.
1
kus = ------------------------------------------------------------ =
1 0.003m 0.002m
--------------- + ------------- + -------------
Vt Vt Vt
12835.8 -------- 17.5 ------ 1.5 ---------
m2 K m K m K
1 12854.8 Vt Vt
= ------------------------------------------------ = -------------- = 12790.84 ---------- ; 1 m2 K 0.003 m2 K 0.002 m2 K 1.005 m2 K m2 K
---------- + ------------- + ----------------
12835.8 Vt 17.5 Vt 1.5 Vt
Demak uskunaning issiqlik uzatish koeffitsenti kus = 12794.84 Vt/m² K.
Keyingi hisobimiz haroratlarning o'rtacha logarifmik farqini aniqlashdan iborat .
Buning uchun agregatning maximal va minimal darajadagi xaroratlarini qabul qilamiz va yuqoridagi (5) formula bilan xisoblaymiz.
Δtmax = 80 0S
Δtmin = 40 0S
Δtmax
Δt o'rt = 0.0023 × ln --------- ; (K)
Δtmin
80 0S
Δt o'rt = 0.0023 × ln --------- = 0.0023 x ln ( 2 0S) = 0.0023 × ln ( 273.15 + 2 0S) =
40 0S
= 0.0023 x ln (275.15) K = 0.0023 x 5.62 K = 0.013 K.
Demak uskuna haroratlarining o'rtacha logarifmik farqi Δt o'rt = 0.013 K
Shu hisoblardan foydalanib agregatning qizdirish yuzasini quyidagi formula orqali topamiz.
8600 Vt 8600
F = ---------------------------------- = ---------------- = 51.54 m2
Vt 166.86
12835.84 ---------- x 0.013 K
m2 K
Demak bak sig'imi 195 l bo'lgan, bir pog'onali ushbu suv qizdirgichning qizdirish yuzasi Fus = 51.54 m² ni tashkil qiladi.
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