2-savol
8-variant
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Berilgan n uchun s ning qiymati hisoblansin:
a) s=1! +2!+3! +4!+…+(1)n+1n!;
b) s=-2!+4!+…+(-1)n(2n)!.
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#include
#include
using namespace std;
int main ()
{int p=1, a, n, s=1;
cout<<"n="; cin>>n;
for(a=1; a<=n; a++)
p=p*a;
s=s+p;
cout<<"s="<
return 0;
}
3-savol
8-variant
8. Butun sonlar ketma-ketligi kiritiladi, 0 - ketma-ketlikning oxiri. Ketma-ketlikdagi 7 ga karra va 5 ga karra bo’lmagan sonlar sonini va manfiy sonlar yig’indisini aniqlang.
#include
#include
using namespace std;
int main ()
{
int a, b, m, summa=0, n;
cout<<"n="; cin>>n;
cout<<"m="; cin>>m;
for(a=n; a<=m; a++)
if(a%5!=0 and a%7!=0 and a<0)
summa=summa+a;
cout<<"summa="<
return 0;
}
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