Toshkent kimyo texnalogiya instuti shahrisabz filiali texnik mexanik fanidan

X. Reduktor korpusining konstruktiv o'lchamlari.
Bir pog’onali reduktor korpusining asosiy elementlari

=0.025a +1=0.025*160+1=5 0.02a 0.02*+1=4.2
b=1.5 =1.5*5=7.5 b₁=1.5 =1.5*4.2=6.3
m= =(0.85:1) (0.85:1)*5=4.5 m₁==(0.85:1) (0.85:1)*4.2=4
d₁=(0.03:0.036)a +12=(0.03:0.036)*160+12=(4:6.92)=6
d₂=(0.7:0.75)d₁=(0.7:0.75)*6=(4.2:4.5)=4.3
d₃=(0.5:0.6)d₁=(0.5:0.6)*6=(3:3.6)=3.5

Foydalanilgan adabiyotlar

1.Sh.A. Shoobidov, S.U.Musayev.Tishli va cherviyakli uzatmalarni loyixalash.Toshkent.2005.
2. Sh.A. Shoobidov, S.U.Musayev.Yuritmalar.Tasmali va zanjirli uzatmalarni
loyihalash.Toshkent.2000.82 b.
3.Nosirov S.N “Mashina detallari” fanidan kurs loyihasini bajarish – T ; Yangi asr avlodi , 2008 y,217 b
4.Kurganbekov M.M, Mirzayev Q.Q, “Mashina detallari” fanidan kurs loyihasini bajarishda “Mexanik
yuritmalarning kinematic hisobi”.Uslubiy ko’rsatma. ToshDTU , 2014 82-b
3.S.A. Chernavskiy i dr. Kursovoe proektirovanie detaley mashin.M..Mashinostroenie.1987 g