Yulduz ⅄ usulida ulanganda Uchburchak ∆ usulida ulanganda

22 Bir fazali tok zanjirida koʼrilgan aktiv, reaktiv va toʼla quvvat tushunchalari uch fazali tok zanjirida ham oʼz maʼnosini toʼla saqlaydi. Yuklama simmetrik va nosimmetrik boʼlganda yulduz va uchburchak usulida ulangan isteʼmolchilarning aktiv, reaktiv va toʼla quvvatlarini hisoblash (aniqlash) formulalari bilan tanishib chiqamiz.
1.Yuklama nosimmetrik boʼlganda har bir fazaning quvvati alohida hisoblab topiladi.
Yulduz ⅄ usulida ulanganda Uchburchak ∆ usulida ulanganda
𝐼_𝐴≠𝐼_𝐵≠𝐼_𝐶 𝐼_𝐴𝐵≠𝐼_𝐵𝐶≠𝐼_𝐶𝐴
Аktiv quvvat
𝑃_𝐴=𝑈_𝐴∙𝐼_𝐴∙cos⁡〖𝜑_𝐴 〗 𝑃_𝐴𝐵=𝑈_𝐴𝐵∙𝐼_𝐴𝐵∙cos⁡〖𝜑_𝐴𝐵 〗
𝑃_𝐵=𝑈_𝐵∙𝐼_𝐵∙cos⁡〖𝜑_𝐵 〗 𝑃_𝐵𝐶=𝑈_𝐵𝐶∙𝐼_𝐵𝐶∙cos⁡〖𝜑_𝐵𝐶 〗
𝑃_𝐶=𝑈_𝐶∙𝐼_𝐶∙cos⁡〖𝜑_𝐶 〗 𝑃_𝐶𝐴=𝑈_𝐶𝐴∙𝐼_𝐶𝐴∙cos⁡〖𝜑_𝐶𝐴 〗., [01.02.2023 12:25]
Uch fazali zanjirning aktiv quvvati alohida fazalar aktiv quvvatlarining yigʼindisiga teng, yaʼni:

𝑷_(⅄ )=𝑷_𝑨+𝑷_𝑩+𝑷_𝑪 𝑷_∆=𝑷_𝑨𝑩+𝑷_𝑩𝑪+𝑷_𝑪𝑨

Reaktiv quvvat
𝑸_𝑨=𝑼_𝑨∙𝑰_𝑨∙𝐬𝐢𝐧⁡〖𝝋_𝑨 〗 𝑸_𝑨𝑩=𝑼_𝑨𝑩∙𝑰_𝑨𝑩∙𝒔𝒊𝒏⁡〖𝝋_𝑨𝑩 〗
𝑸_𝑩=𝑼_𝑩∙𝑰_𝑩∙𝒔𝒊𝒏⁡〖𝝋_𝑩 〗 𝑸_𝑩𝑪=𝑼_𝑩𝑪∙𝑰_𝑩𝑪∙𝒔𝒊𝒏⁡〖𝝋_𝑩𝑪 〗
𝑸_𝑪=𝑼_𝑪∙𝑰_𝑪∙𝒔𝒊𝒏⁡〖𝝋_𝑪 〗 𝑸_𝑪𝑨=𝑼_𝑪𝑨∙𝑰_𝑪𝑨∙𝒔𝒊𝒏⁡〖𝝋_𝑪𝑨 〗

Uch fazali zanjirning reaktiv quvvati alohida fazalar reaktiv quvvatlarining yigʼindisiga teng, yaʼni

𝑸_(⅄ )=𝑸_𝑨+𝑸_𝑩+𝑸_𝑪 𝑸_∆=𝑸_𝑨𝑩+𝑸_𝑩𝑪+𝑸_𝑪𝑨

., [01.02.2023 12:25]

Toʼla quvvat
𝑺_𝑨=√(𝑹_𝑨^𝟐+𝑸_𝑨^𝟐 ) 𝑺_𝑨𝑩=√(𝑹_𝑨𝑩^𝟐+𝑸_𝑨𝑩^𝟐 )
𝑺_𝑩=√(𝑹_𝑩^𝟐+𝑸_𝑩^𝟐 ) 𝑺_𝑩𝑪=√(𝑹_𝑩𝑪^𝟐+𝑸_𝑩𝑪^𝟐 )
𝑺_𝑪=√(𝑹_𝑪^𝟐+𝑸_𝑪^𝟐 ) 𝑺_𝑪𝑨=√(𝑹_𝑪𝑨^𝟐+𝑸_𝑪𝑨^𝟐 )

Uch fazali zanjirning toʼla quvvati

𝑺_(⅄ )=√(𝑷_⅄^𝟐+𝑸_⅄^𝟐 ) 𝑺_∆=√(𝑷_∆^𝟐+𝑸_∆^𝟐 ) Toʼla quvvat
𝑆_𝐴=𝑆_𝐵=𝑆_𝐶=𝑆_𝐹 𝑆_𝐴𝐵=𝑆_𝐵𝐶=𝑆_𝐶𝐴=𝑆_𝐹
𝑆_𝐹=𝑈_𝐹∙𝐼_𝐹 𝑆_𝐹=𝑈_𝐹∙𝐼_𝐹
𝑆_⅄=3𝑈_𝐹∙𝐼_𝐹=3𝑆_𝐹 𝑆_∆=3𝑈_𝐹∙𝐼_𝐹=3𝑆_𝐹

𝑄_𝐴=𝑄_𝐵=𝑄_𝐶=𝑄_𝐹 𝑄_𝐴𝐵=𝑄_𝐵𝐶=𝑄_𝐶𝐴=𝑄_𝐹

𝑄_𝐹=𝑈_𝐹∙𝐼_𝐹∙sin⁡〖𝜑_𝐹 〗 𝑄_𝐹=𝑈_𝐹∙𝐼_𝐹∙sin⁡〖𝜑_𝐹 〗
𝑄_⅄=3𝑈_𝐹∙𝐼_𝐹∙sin⁡〖𝜑_𝐹 〗=3𝑄_𝐹 𝑄_∆=3𝑈_𝐹∙𝐼_𝐹∙sin⁡〖𝜑_𝐹 〗=3𝑄_𝐹

., [01.02.2023 12:27]

2. Yuklama simmetrik boʼlganda
𝐼_𝐴=𝐼_𝐵=𝐼_𝐶=𝐼_𝐹 𝐼_𝐴𝐵=𝐼_𝐵𝐶=𝐼_𝐶𝐴=𝐼_𝐹
𝜑_𝐴=𝜑_𝐵=𝜑_𝐶=𝜑_𝐹 𝜑_𝐴𝐵=𝜑_𝐵𝐶=𝜑_𝐶𝐴=𝜑_𝐹
Аktiv quvvat
𝑃_𝐴=𝑃_𝐵=𝑃_𝐶=𝑃_𝐹 𝑃_𝐴𝐵=𝑃_𝐵𝐶=𝑃_𝐶𝐴=𝑃_𝐹
𝑃_𝐹=𝑈_𝐹∙𝐼_𝐹∙cos⁡〖𝜑_𝐹 〗 𝑃_𝐹=𝑈_𝐹∙𝐼_𝐹∙cos⁡〖𝜑_𝐹 〗
𝑃_⅄=3𝑈_𝐹∙𝐼_𝐹∙cos⁡〖𝜑_𝐹 〗=3𝑃_𝐹 𝑃_∆=3𝑈_𝐹∙𝐼_𝐹∙cos⁡〖𝜑_𝐹 〗=3𝑃_𝐹
Reaktiv quvvat