D chemical 47 a) natural gas burns in stove(chemical)

35 а

37 b

39 ------

41 a

43 a

45a. chemical

b. physical
c. physical
d. chemical

47 a) natural gas burns in stove(chemical)

b)liquid propane in a gas grill evaporates because the valve was left open(physical)

c)liquid propane in a gas grill burns in a flame(chemical)

d)bicycle frame rusts on repeated exposure to air and water(chemical)

49

51 Convert each temperature.

1. 
   32 °F to °C (temperature at which water freezes)= 0℃
   
2. 
   77 K to °F (temperature of liquid nitrogen)=-321.07(°F)
   

c. -109 °F to °C (temperature of dry ice)=42.78 °C

d. 98.6 °F to K (body temperature) =37℃

53 -80 °F≈ -67,7 ° C≈205K

55 a. 1.2 * 10 - 9 m =nano

b. 22 * 10 - 15 s =femto

c. 1.5 * 109 g =giga

d. 3.5 * 106 L=mega

57 a. 4.5 ns =4.5nanosekund

b. 18 fs =18femtosekund

c. 128 pm=128pikometre

d. 35 mm=35milimetre

59 a. 1245 kg 1.245 * 106 g 1.245 * 109 mg

B)515 km 5150000dm 51500000cm

c. 122.355 s 122355ms 0.122355ks

d. 3.345 kJ 3345J 3345000mJ

61 Express the quantity 254,998 m in each unit.

a. 254.998km

b. Mm

c.2549980000 mm

d. 254998000cm

63 10,000 square centimeters

65 density = 7.135g/cm³

67 density=1.26g/cm³

69)Ethylene glycol (antifreeze) has a density of 1.11 g>cm3.

a. What is the mass in g of 417 mL of ethylene glycol? =52.17 g

b. What is the volume in L of 4.1 kg of ethylene glycol?=3.7L

71)mass=201 145 g=201.145 kg

73)a)≈74 b)8.8 c)≈645

75)a) in 1,050,501km underline all zeroes; b) in 0.0020m cross out first 3 zeroes and underline last zero; c) in 0.000000000000002s cross out all zeroes; d) in 0.001090 cm cross out first 3 zeroes and underline last 2 zeroes

77. 
    a. 0.000312 m=3.12*10^-5 m
    

b. 312,000 s

c. 3.12 * 105 km

d. 13,127 s

e. 2000
79 b. 12 in = 1 ft

81

a. 156.852 ≈156.8

b. 156.842 ≈156.8

c. 156.849 ≈156.8

d. 156.899 ≈156.9

83a. 9.15 : 4.970 =1.84

b. 1.54 * 0.03060 * 0.69 =0.32

c. 27.5 * 1.82 : 100.04 =0.5

d. (2.290 * 106) : (6.7 * 104)=0.34*10^2
85a. 43.7 - 2.341≈41.36

b. 17.6 + 2.838 + 2.3 + 110.77≈133.43

c. 19.6 + 58.33 - 4.974 ≈72.96

d. 5.99 - 5.572≈0.42

87a. (24.6681 * 2.38) + 332.58 ≈391.3

b. (85.3 - 21.489) : 0.0059 ≈10815.4

c. (512 : 986.7) + 5.44 ≈5.95

d. [(28.7 * 105) : 48.533] + 144.99≈145.59*10^5

89density (L)≈0.75g/mL
91a. 27.8 L=27800cm3

b. 1898 mg ≈0,0019kg

c. 198 km =19800000 cm
93a. 154 cm ≈60.63 in

b. 3.14 kg=3140 g

c. 3.5 L ≈3.698 qt

d. 109 mm ≈4.291 in in

95t=1.20 hours

97 40.6miles per gallon

99 a) 195 m^2=0.000195 km^2. b)195m^2= 19500dm^2 c)195m^2=1950000cm^2

101)0.6796875square miles

103≈0.4mg

105=31556736 s

107a. volume (extensive )

b. boiling point (intensive)

c. Temperature( intensive)
d. electrical conductivity (extensive)

e. Energy(extensive)

109 no. since in Fahrenheit, which is 1/180 of the difference between the freezing and boiling points of water

111) 10 ton =10000 kg  ,  55 miles =88.5139 km  and 1 hour = 3600 s

55 mile per hour= 0.0245872 km/s=24.5872 m/s

Here m= 10000 kg,  v= 24.5872 m/s   and t= 1 s

= 245872
113 a. 1.76 * 10^ - 3:8.0 * 10^2 =0.22*10^-5

b. 1.87 * 10 - 2 + 2 * 10-4 - 3.0 * 10 - 3 =0.87*10^-3

c. [(1.36 * 10^5)(0.000322):0.082](129.2)=0.69*10^5
115

V=PI x r^2 x h = 3.14 x 3.8^2 x 22 = 997.52 cubic cm

now calculate mass of the gold and the sand

gold = 19.3 x 997.52 = 19252 grams (19.25 kilograms)

sand = 3.00 x 997.52 = 2992.56 grams (2.99 kilograms)
so yes he set the alarm off
117)7.86g/cm³≈0.284 pound per cubic inch.
119)

V= (pi)(r^2)(h)=(pi)(0.5588cm)^2(5.4864cm)= 5.3842cm3

Density = (41.0g) / (5.3842cm3)= 7.6149 g/cm

121

123s=331.8km

125 6.8x10^-15cm³ / 1 cm³

127 2.41 x 10^19 km

129 (2300 x 10^-3 g Na) / (39.33 g Na / 100 g NaCl) / (2.47 g NaCl / 100 g mix) = 237 g mix

131 Density of copper = 8.96 gm cm^-3

Volume of copper = 24000/8.96 cm^3

Volume = area*length

Length = volume/area = (24000/8.96)/(pi*(0.163)^2) cm

Resistance = (24000/8.96)/(pi*(1.63*10^-3)^2)*2.061*10^-5 ohms= 0.66 ohms to 2 dp

133 0.371

135

137

139 0.0972 g = 97 mg CO