O„zbekiston respublikasi xalq ta‟lim vazirligi


Download 0.9 Mb.
bet26/31
Sana26.03.2020
Hajmi0.9 Mb.
1   ...   23   24   25   26   27   28   29   30   31

Javob: x


(2,3]

[11,12)


  1. misol.



log (x2 2
1


5x 6)

tengsizlikni yeching.


Yechish: Tengsizlikning aniqlanish sohasi x2-5x-6>0 yoki

(x+1)(x-6)>0 yoki x (

, 1)



(6,

bo`ladi.



Tengsizlikni qanoatlantiruvchi x ni x 2
5x 6

( 1 ) 3

2

dan yoki x2-5x-


6≤8 yoki (x+2)(x-7)≤0 dan topamiz: -2≤x≤7. Tengsizlikning mavjudlik


sohasi bilan birlashtirib, yechim x

[ 2, 1)


(6,7] ni topamiz.


Tengsizliklarni yeching


1. 1)

log 2 x 3;

  1. log x3 2;

3) log 2,5 x 1;

4) log 3 (x 5) 2;

5) log 0,7 (2x

0,3) 1;

6) log 1 (5x 6) 2.

7



2. 1) lg( 4x 5)

lg( x

1);

2) log 0,3 (2x 3)

log 0,3 (x 2)

  1. log 0,5 x

log 2 (3

2x);



  1. log (x 3)

log x

2log 2.

3. 1)


log (x 2

10x



10)

0; 2)


log (x 2 5

3x 3) 0;

3) log (x2
1,2

4

0,6

12x



21)

0; 4)


log (x2

5x 6) 3.




4. 1) log 2 x 4 0;
0,5

2


    1. log 1 x 9 0;



2

    1. log 0,5 x

5) 3log x

log 2 (3

2.

2x);

4) 2


log 2 x 1;




Download 0.9 Mb.

Do'stlaringiz bilan baham:
1   ...   23   24   25   26   27   28   29   30   31




Ma'lumotlar bazasi mualliflik huquqi bilan himoyalangan ©fayllar.org 2020
ma'muriyatiga murojaat qiling