Raximov Doston 218 18


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Shifrator



10×5 shifrator shartli belgilanishi, ME asosidagi tuzilma sxemasi va haqiqiylik jadvali keltiring.



X0

X1

X2

X3

X4

X5

X6

X7

X8

X9

Q0

Q1

Q2

Q3

Q4

1




























0

0

0

0

0




1

























1

0

0

0

0







1






















0

1

0

0

0










1



















1

1

0

0

0













1
















0

0

1

0

0
















1













1

0

1

0

0



















1










0

1

1

0

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1







1

1

1

0

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1




0

0

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1

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1

1

0

0

1

0

Q0 = x1 + x3 + x5 + x7 + x9


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