Yig’indisi 35 ga teng bo’lgan uchta son o’suvchi geometrik progressiyaning dastlabki uchta hadlaridir


Download 11.33 Kb.
Sana10.02.2023
Hajmi11.33 Kb.
#1186190
Bog'liq
progressiya test


1-misol
Yig’indisi 35 ga teng bo’lgan uchta son o’suvchi geometrik progressiyaning dastlabki uchta hadlaridir . agar shu sonlardan mos ravishda 2, 2 va 7sonlarini ayirilsa, hosil bo’lgan sonlar arifmetik progressiyaning ketma - ket hadlari bo’ladi . Arifmetik progressiyaning dastlabki 10 ta hadining yig’indisini toping.
A)245 B)275 C)255 D) 265 E)235
3-misol
Ikkinchi hadi 6 ga teng birinchi uchta hadining yig’indisi 26 ga teng o’suvchi geometrik progressiyaning uchinchi va birinchi hadlari ayirmasini toping
A)15 B)16 C)14 D)13 E)12
5-misol
Agar geometrik progressiyada + + =17 bo’lsa, ni toping
A)4 B)3 C)2 D)1 E)6
Misol
Kamayuvchi geometrik progressiya tashkil etuvchi uchta sondan uchinchisi 18 ga teng . Bu son o’rniga 10soni olinsa , uchta son arifmetik progressiya tashkil etadi. Birinchi sonni toping.
A)50 B)60 C)40 D)27 E)36
7-misol
2, , va sonlari o’suvchi geometrik progressiyaning dastlabki uchta hadidan iborat.Agar bu progressiyaning ikkinchi hadiga 4 qo’shilsa , hosil bo’lgan sonlar arifmetik progressiyaning dastlabki uchta hadini tashkil etadi. Berilgan progressiyaning maxrajini toping.
A)3 B)2 C)2,5 D)3,5 E)1,5
9-misol
Geometrik progressiyaningmaxraji 3 ga , dastlabki 4 ta hadlari yig’indisi 80 ga teng . Uning to’rtinchi hadini toping.
A)24 B)32 C)54 D)27 E)57
11-misol
Geometrik progressiyaning dastlabki uchta hadi yig’indisi -26 ga , dastlabki to’rttasiniki esa -80 ga teng .Agar shu progressiyaning birinchi hadi -2 ga teng bo’lsa, uning maxraji qanchaga teng bo’ladi?
A)3 B)-3 C)-2 D)2 E)4
13-misol
Ishorasi almashinuvchi geometrik progressiyaning birinchi hadi 2 ga , uchinchi hadi 8 ga teng . Shu progressiyaning dastlabki 6 ta hadi yig’indisini toping.
20 B)-20 C)-42 D)42 E)-64
15-misol
5 ta haddan iborat geometrik progressiyaning hadlari yig’indisi birinchi hadini hisobga olmaganda 30 ga oxirgisini hisobga olmaganda 15 ga teng. Shu progressiyaning uchinchi hadini toping.
A)6 B)8 C)4 D)10 E)12

  1. misol

Oltita haddan iborat geometrik progressiyaning dastlabki uchta hadining yig’indisi 168 ga, keyingi uchtasiniki esa 21 ga teng.
Download 11.33 Kb.

Do'stlaringiz bilan baham:




Ma'lumotlar bazasi mualliflik huquqi bilan himoyalangan ©fayllar.org 2024
ma'muriyatiga murojaat qiling