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funksional analiz misol va masalalar yechish 1 qism

M
= max
x
[01]
|f(x)|,
 
lim
n
→∞
k
(k − 1)
2n
= 1.
2

!


lim
n
→∞
1
n
n


=1
f
(x

) =
$
1
0
f
(x)dx.
\ 
{x
n
}

"

[01]

 

 

 


$9
(+0+
0-

/

 
5

5
!5


5




&
5
  
5
  


 
'
5


!5
  
5
 

.
5


5
  
5
!5


5

 

/
5


5


  
!5
  


 

5
α
∈ (02)


  
α
≥ 2


 


5

  
5
α
∈ (02)


  
α
≥ 2


 


f
(x) = x
α
, α >
1

&
1

 

 
'
f
(x) =

x.
.
5
, 

 
5



 

 
#a#8"  

%
f
(x) = a ± x, x ∈ R.
&
R
2
 

 

 

(
f
(x
1
, x
2
) = (x
1
cos ϕ − x
2
sin ϕ a
1
, x
1
sin ϕ x
2
cos ϕ a
2
)


g
(x
1
, x
2
) = (x
2
, x
1
)
 
  
 


 


 

$'
5

5
_

%9
@2
0
"
-
'

'
a <
1.

5
x
= 1414

5
x
= 3321

!5
x
2369

%
2

.
λ
∈ (−q, q)< q < 1.

λ
∈ (01).
&9
"0
,+
0
0
 
$
A

 &
& 

 
!


  
ε >
0


A
ε
!
  
ε


+
B
⊂ A

  
!


A
ε
& 
B
!



!
  
ε


 
#8#"  

&
B


 &
& 

 
%
X
= R, A = [01] , B = (01) .
&
#8a" 



 


'
5
ε
= 05

5
ε
=
1
2n

.
ε
=

2
2

/
1
 
b

M
1
(21), M
2
(23), M
3
(41)


M
4
(43)

  

&
& 
A
!







ε
=

2

3#8#"
!
 5

 
")"#


X
= R, M = (01), f(x) =
1
x

 
X
= R
2
, M
{(x, y) : = 0} , F =

(x, y) : x > 0, y x
1



 
M
 
y
x

!
 
F
 

 &  

y
x

 



 

 



!
 
 
 
$
' 



+
 

5
5
5


!
 "
 
.
C
(1)
[a, b]
 

K
& 


 &

 
!




!
  
 
 


  


+
 

 




 
/
M
2
, M
3
, M
4
.

lim
n
→∞
a
n
= 0.






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