3-amaliy ish. Quyidagi ifodaga mos mantiqiy sxemani chizing va

3-amaliy ish. Quyidagi ifodaga mos mantiqiy sxemani chizing va
mantiqiy ifodaning qiymatini toping.
F = (A̅&B̅) ∨ (B̅&C̅), аgаr A=1, B=1, C=0
Avvalambor mantiqiy ifodani soddalashtirib olsak (agar iloji bo’lsa) maqsadga
muvofiq bo’ladi.

Endi esa uning mantiqiy sxemasi va rostlik jadvalini tuzamiz:

a	b	с	⌐b	⌐a	⌐c	(⌐a) v (⌐c)	(⌐b) & ((⌐a) v (⌐c))
0	0	0	1	1	1	1	1
0	0	1	1	1	0	1	1
0	1	0	0	1	1	1	0
0	1	1	0	1	0	1	0
1	0	0	1	0	1	1	1
1	0	1	1	0	0	0	0
1	1	0	0	0	1	1	0
1	1	1	0	0	0	0	0

4-amaliy ish. Quyida keltirilgan ifoda uchun assembler tilida dastur
tuzing:

10bc+2ac;

MOV	ECX, c	ECX = c
MOV	EAX, a	EAX = a
IMUL IMUL	EAX, c EAX, 2	EAX = EAX * c = ac EAX = EAX * 2 = 2ac
MOV	EBX, b	EBX = b
IMUL	EBX, c	EBX = EBX * c = bc
IMUL	EBX, 10	EBX = EBX * 10 = 10bc
ADD	EAX, EBX	EAX = EAX + EBX = 2ac + 10bc
MOV	result, EAX	result = EAX =10bc+2ac
JMP	DONE	DONE ga o’tish