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O M K A 145. • • • • • • • OA nurda joylashgan K nuqtaning


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O M K A
145. • • • • • • • OA nurda joylashgan K nuqtaning
0 1 2 7
kordinatasini toping.

  1. K(7) b) K(3)

s) K(4) d) K(2)
146. Agar a=4325, b=3 bo’lsa, a×b ifodaning qiymatini toping.
a) 11785 b) 12975
s) 10695 d) 13874

Nollar bilan tugaydigan sonlarga bo’lish.
147. Sayyohlar 90 km yo’lni o’tishni mo’ljalladilar. Bir kun yo’lda bo’lganlaridan so’ng, ular yana birinchi kun o’tgan yo’llarining yarmicha yo’lni o’tishlari kerakligini tushundilar. Sayyohlar yana necha km yo’l yurishlari kerak?
a) 40 km b) 25 km
s) 30 km d) 35 km
148. Qoldiqli bo’lishni bajaring va to’g’ri javobni belgilang: 1921÷6=
a) 32 (1q) b) 33 (1q)
s) 30 (2q) d) 32 (3q)
149. Ayirmani toping: 54265-32362=
a) 20908 b) 21913
s) 21912 d) 21903
150. Amallarni bajaring va to’g’ri javobni belgilang: 290×(478+342)=
a) 136700 b) 237800
s) 237600 d) 231900

151. 9 2 3
7 2 8
1 0 1 7 1 Bosh katakchalarga mos sonni qo’ying.

  1. 2; 4 b) 1; 5

s) 3; 4 d) 4; 3
152. Bo’linmani toping: 18200÷700=
a) 25 b) 30
s) 26 d) 24
Mustahkamlash uchun mashqlar.
153. Ifodalarni taqqoslang: 15×10×4 va 15×(10×4); 210÷(10×3) va 210÷10÷3
a) 15×10×4=15×(10×4); 210÷(10×3)=210÷10÷3
b) 15×10×4>15×(10×4); 210÷(10×3)=210÷10÷3
s) 15×10×4<15×(10×4); 210÷(10×3)>210÷10÷3
d) 15×10×4=15×(10×4); 210÷(10×3)<210÷10÷3
154. Amallarni bajaring va to’g’ri javobni belgilang: 37127-321×5+20731=
a) 562255 b) 55253
s) 563256 d) 56253
155. 7200 sonini 290 va 200 sonlarining ayirmasiga bo’ling.
a) 90 b) 80
s) 60 d) 70
156. Tenglamani yeching: 30×X-70=350
a) X=15 b) X=16
s) X=14 d) X=19

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