6 – sinf Matematika Nazorat ishi №1 I variant

6 – sinf Matematika Nazorat ishi № 13
I variant

1. 
   Praporsiyani yeching.
   
2. 
   Teng yonli uchburchakningyon tomoni 10sm eremetri 30 sm bo’lsa uchbrchakning asosini toping?
   
3. 
   Teng tomonli uchburchakningperemetri 2796 sm bo’lsa uning tomonini toping?
   
4. 
   Uchburchakning tomonlari bo’lsa uning peremetrini toping?
   
5. 
   Tenglamani yeching (7x+3) – (5x-7) = (2x-5) – (3x+6)
   

II variant

1. 
   Praporsiyani yeching.
   
2. 
   Teng yonli uchburchakningyon tomoni 12 sm eremetri 36 sm bo’lsa uchbrchakning asosini toping?
   
3. 
   Teng tomonli uchburchakningperemetri 3456 sm bo’lsa uning tomonini toping?
   
4. 
   Uchburchakning tomonlari bo’lsa uning peremetrini toping?
   
5. 
   Tenglamani yeching 3(2x-3) + 4(2-5x) = 7(2-3x) – 2(3x-1).
   

6 – sinf Matematika Nazorat ishi № 14
I variant

1. 
   Tenglamani yeching. 2x+1+3(x-2) = 14.
   
2. 
   Praporsiyani yeching.
   
3. 
   Hisoblang. (-14,4)*(-2) : (-3,6)*(-1)
   
4. 
   To’rtta sonning yig’indisi. 3888 ga teng 4:3:5:6 nisbatta bo’lsa shu sonlarni toping va eng kattasi bilan eng kichigining ayirmasini hisoblang?
   
5. 
   Uchburchakning peremetri 61 sm uning bir tomoni ikkinchisidan 3 sm qisqa uning uchinchisidan 5 sm uzun. Shu uchburchakning tomonlarini toping?
   

II variant

1. 
   Tenglamani yeching. 2(x-4) - 5(x-6) = 1.
   
2. 
   Praporsiyani yeching.
   
3. 
   Hisoblang. (-33,6): 2,8 * (-3,5):(-7)
   
4. 
   To’rtta sonning yig’indisi. 3888 ga teng 4:3:5:6 nisbatta bo’lsa shu sonlarni toping va eng kattasi bilan eng kichigining yig’indisini hisoblang?
   
5. 
   Uchburchakning peremetri 69 sm uning bir tomoni ikkinchisidan 3 sm qisqa uning uchinchisidan 5 sm uzun. Shu uchburchakning tomonlarini toping?