Algebra tushunchasi

2.;

Matematik induksiya yordamida isbоtlang

1) n=1 uchun 1=

2) n=k 1+2+3+…+k= deb olib,

3) n=k+1 1+2+3+…+k+(k+1)=ni isboti.

1+2+3+...+k+(k+1)=+(k+1)=

.

3. Matematik induksiya yordamida isbоtlang.

,

.





2;

= .

4. 
   Matematik induksiya yordamida isbоtlang.
   

1. 
   n=1; 1*2=
   
2. 
   n=k ; 1*2+2*3+3*4+...+k(k+1)=
   
3. 
   n=k+1; 1*2+2*3*4+k(k+1)+(k+1)(k+2)=
   

Isbot. 1*2+2*3+3*4+k(k+1)+(k+1)(k+2)=(k+1)(k+2)=

=(k+1)(k+2)=(k+1)(k+2)= .

3. 
   – topshiriq:
   

1. 
   Ko‘paytmani yoyib yozing:
   

2) ; 3) ; 4) ; 5)

1)