Assignment Problem 1

Assignment

Problem 1
find the absolute extreme in the interval



Problem 2


Problem 3

(-2 cannot be solution because it is located in the interval).
Problem 4

1. 
   
   
2. 
   
   

Problem 5

1. 
   Find: the domain, range, intercepts, asymptotes, symmetry, relative extreme, points of inflection, and concavity for the function.
   

Domain: Because you can put any number into the argument.
Range: Because the lowest function value is 0 when the argument equals to 2 or-2
Intercepts: (0;16), (-2;0), (2;0)

Symmetry:
Relative extremes: (-2;0), (2;0)
Points of inflection: so, it has no that kind of points
Concavity: which means only one upward.
Asymptotes: Not available.

2. 
   Find: the domain, range, intercepts, asymptotes, symmetry, relative extreme, points of inflection, and concavity for the function.
   

Domain: Because you can put any number into the argument.
Range:
Max(1;1) Min(-1;-1)
Intercepts:
Symmetry:
Relative extremes: Max (1;1) Min (-1;-1)
Points of inflection:
Concavity: upward , downward
Problem 6
Find the point on the graph of that is closest to the point (6;0).
– the distance between two points
If I need to find the closest point to (6;0) on the graph, I should mark this point, as . In that case, the point (6;0) will be respectively.



Problem 7
To find the dimensions, firstly, I need make two square shaped corrals to maximize area. Every square is a rectangle then I mark the length of square’s one side, as x. Totally, there are 2 squares and every square has 4 sides.
4x*2=400 8x=400 x=50 So the length of the square’s every side must equal to 50 ft