Berilgan: K=125 N/m t=8s N=5 m=? Yechilishi

Javob: C) 𝑥 = 0.12 cos 2 0𝑡.
27.12. Massasi 0,1 kg bo'lgan prujinali mayatnikning tebranish qonuni 𝑥 = 0.05 sin 1 0𝑡(m) ko’rinishga ega. Prujinaning bikrligini toping.
A) 1,6 B) 10
C) 5 D) 6.4
Yechilishi: Yugoridagi formulaga asosan quyidagi ifodalami yozamiz:

𝑘 ² = 𝑘 ; 𝑘 = 𝜔²𝑚
𝜔 √ ; 𝜔 𝑚
.
Berilgan harakat tenglamasiga asosan siklik chastota quyidagiga teng: 𝜔 = 10 rad/s;

²𝑚10² ⋅ 0.1 = 10 𝑁
𝑘 = 𝜔
𝑚
Javob: B) 10.
𝜋 5𝜋
27.13. Kosinus qonuni bo'yicha garmonik tebranayotgan nuqtaning fazadagi siljishi 1 sm bo'lsa,
3 3 fazadagi siljishi qanday (sm) bo'ladi?
A) 0,5 B) 1 C) 1,25 D) 2,5
Berilgan:
𝜋
𝜑₁ = ₃ Yechilishi: Har ikki holat uchun tebranish harakat tenglamasini 𝑥₁ = 1 𝑠𝑚 =
0.01 𝑚 yozib, ularning nisbatini olamiz.
5𝜋
𝜑₂ =
3

𝑥2 =?

𝑥 = 𝑥𝑚𝑐𝑜𝑠𝜑

𝑥₁ 𝑥 𝑐𝑜𝑠𝜑 𝑐𝑜𝑠𝜑₁

𝑥₂ 𝑥_𝑚𝑐𝑜𝑠𝜑₂ 𝑐𝑜𝑠𝜑₂
𝑥
𝑥₂ = 1𝑐𝑜𝑠𝜑2 = 0. 3 = = 0.01 = 1𝑠𝑚
𝑐𝑜𝑠𝜑
Javob:B)1
27.14. Oanday fazalarda siljish modul bo' yicha amplitudaning miga teng bo 'ladi? Tebranishlar kosinus gonuni bo 'yicha ro'y beradi
𝜋 𝜋 𝜋 𝜋
A)+ ± 𝜋𝑛 B) C) D)± ± 2𝜋𝑛

4 3