Berilgan:
T=6s Yechilishi: Tebranish muvozanat vaziyatidan bosh-angani uchun tenglama sinus
π₯π
π₯ = qonuniga bo'ysunadi.
2
t=?
π₯π
π₯ = π₯ππ ππππ‘; 2 = π₯ππ ππππ‘;
π 1
π ππππ‘ = ; sin = ;
6 2
π π 2π π π
= ππ‘; = π‘; π‘ = = = 0.5π .
6 6 π 12 6
Javob: C) 0,5.
28-Β§. Matematik mayatnik
28.1. Ikkita matematik mayatnikdan birining tebranish davri 0,5 s. Agar birinchi mayatnik 6 marta tebrangan vaqtda ikkinchisi 4 marta tebransa, ikkinchi mayatnikning tebranish davri qanday bo'ladi?
A) 75 B) 7,5 C) 0,75 D) 0,075
Berilgan:
π1 = 0.5βπ
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Yechilishi: Tebranish davrining TeTebranishlar soniga bogβliqlik
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π1 = 6
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formulasidan foydalanamiz.
π‘ π‘
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π2 = 4 π1 = π1 ; π2 = π 2 nisbatini olamiz.
π‘
π1 =? ππ12 = ππ‘1 = ππ21 = = ;
π2
π 75βπ
Javob: C) 0.75.
28.2. Matematik mayatnikning tebranishlari amplitudasi 2 marta oshsa.uning kichik teb ranishlari davri qanday o'zgaradi?
A) o'zgarmaydi B) 2 marta ortadi C )2 marta kamayadi D) 4 marta ortadi
Berilgan:
π΄1 = 2π΄1 Yechilishi: Matematik mayatnikning tebranish davri ifodadan ko'rinib
π1
=? turibdiki, tebranish davri amplitudaga bogβliq emas.
π2
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