Convergence of the empirical two-sample -statistics with -mixing data


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jn1 , jn2


jn1 , jn2

→ 0 in probability;

→ 0 in probability.
(2.37)

(2.38)

In order to prove (2.35) and (2.36), we need to control the differences in s and t.

Let us show (2.35). We first control |ξn (s, t) − ξn (s, t0)| for t0t > 1/n. By definition of ξn,







ξn (s, t)




ξn (s, t0) 6

n 3[/2

0

]




(as (Xi)




ms)




3/[

2

]




(as (Xi)




ms)

|






|




nt







[nt0]








n

nt







[nt]












n










i=1







n










i=1































X

























X
















































































































































































































+ [ 3/02]

(bs (Xi)

ms)

[ 3/2]

n

n



n

i=[nt ]+1




nt

X0




nt

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