Cours project by discipline «basic technological processes and devices» content

Using the nominal heat exchange surface table, we determine the following:
Diameter of heating chamber D = 1000 mm
Separator diameter D = 3000
Device height H = 23500 mm
Device mass m = 19100 kg
Pipe diameter d = 38x2 mm
The number of pipes in the heating chamber is n = 355
Determination of the diameter of the nozzles:
D=√(4*G)/(π*w*p)
For heating water steam input.
D=√4.89/(0.785*0.75*30)=0.526m*1000=526mm≈550mm
For secondary steam output.
D=√(4*4.74)/(3.14*25*0.964)=0.106m*1000=106mm≈150mm
For solution penetration.
D=√7.417/(0.785*1215.6*0.5)=0.125m*1000=125mm≈150mm
For solution release.
D=√(4*2.67)/(3.14*0.7*1215.6)=0.063m*1000=63mm≈80mm
To drain the condensate that has condensed in the heating chamber.
D=√4.89/(0.785*978*2)=0.056m*1000=56mm≈100mm

5.Hydraulic calculation
The lost pressure is found from the hydraulic calculation. Using it, a suitable pump is selected.
Pressure is lost due to local and frictional resistances in the device. It is determined using the following formula.
ΔP=(((λ*(l/d_e))+Σξ)*((w²*p)/2))
w=velocity of the solution=0.0093m/sec
w=((G*4*z)/(3.14*p*d²*n))=((7.417*4*1)/(3.14*1215.6*0.038²*355))=0.015m/sec
l = pipe length - 5 m
d_e = pipe diameter - 0.038 m
µ = coefficient of dynamic viscosity –1.24∙ 10⁻³𝑃𝑎 ∙ 𝑠
r = density of solution -1215.6 kg/m³
λ = coefficient of frictional resistance - 0.695
To determine it, it is necessary to determine the criterion Re in the pipes:
Re=((G*4*z)/(3.14*µ*d*n))=((7.417*4*1)/(3.14*0.038*355*1.24*10^-3))=564.84
So the regime is laminar. Using it, we find λ = coefficient of friction resistance as follows. The coefficient of frictional resistance for circular pipes in the laminar regime is found as follows.
λ=64/Re=64/564.84=0.11
∑ 𝜉 = sum of local resistance coefficients 7.4 We use appropriate tables to determine it.

1. 
   Enter and exit of the chamber-ξ₁=3;
   
2. 
   Enter and exit of the tube-ξ₂-2;
   
3. 
   Turning to 90⁰-ξ₃=1.2*2=2.4
   

Total: Σξ=7.4
ΔP=((0.695*4/0.038+7.4)*(0.0093²*1215.6/2))=4.2 Pa