Diskret tuzilmalardan 1-oraliq nazorat varianti №1


Diskret tuzilmalardan 1-oraliq nazorat varianti


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TEST ДТ Оралиқ назорат (1)


Diskret tuzilmalardan 1-oraliq nazorat varianti

13



  1. Agar A = {x∈N: x2 + x − 20 = 0}, B = {x∈R: x2 − 7 x +12 = 0 }, u holda A ∩ B nimaga teng?

A) {− 5;4} B) {4} C) {4;3} D) ∅ E) to`g`ri javob yo`q
2. А={1, 2,3} и В={a, b,c} to`plamlar Dekart ko`paytmasidan munosabatlar aniqlangan. Bulardan qaysi biri biyektiv funksiya bo`ladi: f: A→B ?

A) {(1,b)} B) {(1,a),(2,b)} C) {(1,a), (2,c)} D) {(1,a),(3,c),(2,a),(2,b)}

E) {(1,b),(2,a),(3,c)}
3. А={1, 2} va В={3, 4} to`plamlarning Dekart ko`paytmasini toping.
A) {1, 2, 3, 4} B) {(1,2),(3,4)} C) {(1,3), (2,4)} D) {(1,3),(1,4),(2,3),(2,4)} E) {(3,1),(3,2),(4,1),(4,2)}
4. maxraji 50 ga teng nechta nomanfiy qisqarmaydigan to`g`ri kasr mavjud?

A) 60 B) 10 C) 20 D) 35 E) 56


5 . 5 ta bir xil o`yin kubigini tashlaganda nechta har xil sonlar tushishi mumkin?

А) 252 B) 156 C) 120 D) 36 E) 1024


6. Agar A –barcha mumkin bo’lgan to’g’ri burchakli uchburchaklar to’plami, B-romblar to’plami, u holda

A ∩ B =?


  1. romb B) ∅ C) uchburchak D) kvadrat

7. Agar A = {x∈N: x2 + x − 20 = 0}, B = {x∈R: x2− 7 x +12 = 0 },u holda A ∩ B =?

A) {4} B) {5} C) {4,5} D) {6}
8. Quydagini soddalashtiring: A \B A B ) \ A


  1. ∅ B) A B C) A B D) A B

9. To’plamlarni dekart ko’paytmasidaА={1, 2} va В={a,b,c} munosabatlar aniqlangan.Qaysi munosabat inyektivlik funksiyasi f: A→B bo’ladi?

A) {(1,b),(2,a),(1,c)} B) {(1,a)} C) {(1,a), (2,a)} D) {(1,a),(2,c)} E) {(1,a),(2,b),(1,c),(2,c)}
10. Axborot texnologiyalari mutaxassisi har kuni Internetda 6 ta saytga kiradi. Agar saytlarga kirish tasodifiy hodisa bo`lsa, mutaxassis nechta usulda saytlarni kuzatadi.

А) 24 B) 120 C) 5! D) 50 E) 720


11 . 52!/50! ni hisoblang.

A) 2652 B) 2684 C) 2680 D) 2180 E) 2120
12. Hisoblang.

A) 4; 6 B) 6; 25 C) 20 D) 9; 4 E) 4; 5


13. (x+2)7 binom yoyilmasining oxirgi hadini toping.

A) 182 B) 10 C) 86 D) 128 E) 102

14. Tenglamani yeching.

A) 12 B) 8 C) 6 D) 7 E) 2


Diskret tuzilmalardan 1-oraliq nazorat varianti

14

1. А={1, а, 2, b, 3, c}, B={1, 2, 3}, C={a,b,c} to`plamlar berilgan. Quyidagilardan qaysi biri to`g`ri:

a) A⊆B∩С б) А⊆С∪В в) B⊆A\С г) С⊆B\A д) В⊆С∩А е) С⊆В∩А


A) а, б B) б, в C) г D) д, е E) г, е
2. Agar A –barcha to`g`ri to`rtburchaklar to`plami, B-romblar to`plami bo`lsa, u holda A ∩ B – qanday to`plam?

A) kvadratlar B) uchburchaklar C) ∅ D) romblar E) to`g`ri javob yo`q


3. А={1,2,3,4,5}, B={3,5,7}, C={3} to`plamlar berilgan. Quyidagilardan qaysi biri to`g`ri:

a) A⊆B б)А⊆С в) B⊆A г) С⊆А д) В⊆С е)С⊆В


A) а, б, д B) б, д C) г, е D) д E) е
4. А to`plam 2 ga bo`linadigan 5 ta sonni, 3 ga bo`linadigan 7 ta va 6 ga bo`linadigan 2 ta sonni o`z ichiga olgan. Agar A t`oplamning elementlari 2 ga yoki 3 ga bo`linadigan bo`lsa, A ning nechta elementi bor?

A) 60 B) 10 C) 30 D) 35 E) 56


5. yig`indi nimaga teng?

A) B) C) D) E)


6. Talaba 8 kunda 4 ta imtihonni topshirishi kerak. Kuniga bittadan ortiq imtihon topshirish mumkin bo`lmasa, u buni nechta ussulda bajarishi mumkin?

A) 860 B) 1680 C) 720 D) 32 E) 8!4!


7. To’plamni ro’yxat tarzida bering: A={12 soni 2 ga bo’linadi}

А) {1,2,3,6} B) {12,14,36,…} C) {1,2,3,4,6,12} D) {1;12}


8. Quydagi to’plamlar berilgan bo’lsin А={1, 2} и В={3, 4}. Dekart ko’paytma A×B qaysi javobda berilgan

  1. {1, 2, 3, 4} B) {(1,3), (2,4)} C) {(1,3),(1,4),(2,3),(2,4)} D) {(3,1),(3,2),(4,1),(4,2)}

9. Quydagi to’plamlarni dekart ko’paytmasi neshta elemendan iborat bo’ladi. A = {1;2;3} va B = {3;4}

A) 10 B) 15 C) 30 D) 6 E) 16
10. To’plamlarni dekart ko’paytmasida А={a, b} va В={1,2} munosabatlar aniqlangan.Qaysi munosabat suryektivlik funksiyasi f: A→B bo’ladi?

A) {(a,1), (b,2)} B) {(a,1),(b,1),(a,2)} C) {(a,2)} D) {(a,2),(b,2)}



11. ni hisoblang.

A) 40320 B) 84440 C) 68020 D) 18050 E) 12046
12. Hisoblang.

A) 204 B) 1440 C) 260 D) 229 E) 250


13. (x+2)7 binom yoyilmasining 7-hadi oldidagi koeffitsiyentni toping.

A) 12 B) 10 C) 6 D) 7 E) 12

14. Tenglamani yeching.

A) 12 B) 4 C) 6 D) 5 E) 2



Diskret tuzilmalardan 1-oraliq nazorat varianti

15


1. Elementlarini raqamlab chiqish mumkin bo`lgan cheksiz to`plam...

A) chekli B) sanoqli C) ∅ D) ekvivalent E) to`g`ri javob yo`q


2. A ={1;2;3}; B = {4;5;6}; C = {7;8;9} to`plamlar berilgan. D = A U B U C to`plamning elementlari soni nechta?

A) 3 B) 6 C) 9 D) 5 E) 4


3. А={1, 2, 3, 4} to`plamning dekart kvadratida R={(1,2),(1,4),(2,1),(3,4),(4,1),(4,3)} munosabat

а) refleksivlik, б) simmetriklik в) tranzitivlik, г) antisimmetriklik xossalaridan qaysi birini qanoatlantiradi


A) а B) б,в C) в,г D) б E) г
4. “DOMINO ” so`zidan unli va undosh harflarni nechta usulda tanlash mumkin?

A) 120 B) 9 C) 10 D) 11 E) 12


5. n ta elementdan k tadan guruhlashlar soni

A) B) C) D) E)
6. Mashinada haydovchini ham hisobga olganda 6 ta o`rin bor. 6 kishidan 4 tasida haydovchilik guvohnomasi bo`lsa, ularni nechta ususlda joylashtirish mumkin?

A) 1440 B) 240 C) 480 D) 360 E) 2880


7. To’plam А={1,2,3,4,5,6}. A – to’plamdagi x y binar munosabatning qism to’plami qaysi javobda ko’rsatilgan

A) {(1,1), (1,2), (3,6), (5,6)} B) {(1,2), (2,5), (4,2)} C) {1, 2, 3, 4} D) {(1,3), (2,4)}


8. Qurilish brigadasida 15 talaba bor. Ularning har biriga 15 ta har xil vazifa taqsimlandi. Talabalar nechta usul bilan vazifalarni o`zaro taqsimlab olishlari mumkin?

А) 2*15! В) 215 C) 30 D) 15! E) 30!


9. 123456789 soni raqamlarini nechta usul bilan joylashtirish mumkin, bunda juft raqamlar juft o`rinlarda qolishi kerak?

А) 2880 B) 120 C) 36 D) 24 E) 12036


10. 5 ta qora va 5 ta oq shashkani nechta usulda bitta qatorga terish mumkin?

A) 252 B) 154 C) 360 D) 180 E) нет правильного ответа


11. Matematikadan konferensiyada 4 talaba А, Б, С, Д qatnashishi kerak. Agar Б talabaning qatnasha olmasligi ma`lum bo`lsa, qolgan talabalarni ma`ruzachilar ro`yhatiga nechta usulda joylashtirish mumkin?

А) 24 B) 20 C) 4! D) 50 E) 12

12. Hisoblang.

A) 204 B) 9 C) 260 D) 229 E) 250


13. (x+2)7 binom yoyilmasining 6-hadi oldidagi koeffitsiyentni toping.

A) 12 B) 10 C) 6 D) 21 E) 12



14. Tenglamani yeching.

A) 12 B) 10 C) 6 D) 4 E) 2



Diskret tuzilmalardan 1-oraliq nazorat varianti

16


1. A = {1;2;3} va B = {3;4} to`plamlarning dekart ko`paytmasidan iborat to`plamning nechta elementi bor?

A) 1 B) 3 C) 4 D) 5 E) 6


2. А={1,2,3,4,5,6}. x y binary munosabat yordamida tuzilgan qism to`plamni toping
A) {(1,2), (2,5), (4,2)} B) {(1,1), (1,2), (3,6), (5,6)} C) {(2,1), (6,4)} D) {(3,7)} E) {(2,3),(5,3)}
3. A to`plamdagi R binar munosabat tranzitivlik xossasini qanoatlantiradi, agarda

A) xRx a to`plamdagi ixtiyoriy x uchun ; B) xRy dan yRx kelib chiqadi; C) xRy va yRx dan x=y kelib chiqadi; D) xRy va yRz dan xRz kelib chiqadi


4. 1 dan 20 gacha bo`lgan natural sonlar ichidan yig`indisi toq son bo`lgan 2 ta sonni nechta usulda tanlash mumkin?

A) 80 B) 90 C) 100 D) 110 E) 120


5. 12 ta predmetni 3 ta qutiga nechta ussulda joylash mumkin?

А) 91 B) 27 C) 88 D) 36 E) 120


6. Bitta ham elementga ega bo’lmagan to’plam

  1. cheksiz to`plam B) bo`sh to`plam C) chekli to`plam D) nol

7. А={1,2,3,4,5,6} to’plamdagi «o’zaro tub» binar munosabatning qism to’plami

A) {(1,1), (1,2), (3,6), (5,6)} B) {(1,2), (2,5), (4,2)} C) {1, 2, 3, 4} D) {(2,3),(5,3)}
8. Qirrasining uzunligi 1 dan 10 gacha butun son bo`lgan hechta turli to`g`ri burchakli parallelepiped qurish mumkin?

А) 220 B) 156 C) 84 D) 36 E) 1024


9.”LAZIZ” so`zini nechta usul bilan shifrlash mumkin?

A) 5! B) 4! C) 60 D) 120 E) 3!2!


10. 100 tа tаlаbа sessiya tоpshirishdi. Tаriхni 48 kishi, fаlsаfаni 42 kishi, mаtemаtikаni 37 kishi tоpshirdi. Tаriх vа fаlsаfаni 76 kishi, tаriх vа mаtemаtikаni hаm 76 kishi, fаlsаfа vа mаtemаtikаni 66 kishi tоpshirdi. Hаmmа imtihоnlаrni 5 kishi tоpshirdi. Umuman topshira olmaganlar nechta?

A) 12 B) 10 C) 3 D) 6 E) 8


11. 5!+6! ni hisoblang.

A) 840 B) 84 C) 680 D) 180 E) 120


12. Hisoblang.

A) 4 B) 6 C) 20 D) 9 E) 5


13. (a+b)10 binom yoyilmasining 2-hadi oldidagi koeffitsiyentni toping.

A) 12 B) 16 C) 6 D) 10 E) 14


14. Tenglamani yeching.

A) 12 B) 10 C) 6 D) 7 E) 2



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