«elektr stansiyalari,tarmoqlari va tizimlari»


Liniyaning boshlanishida quvvat va kuchlanish berilgan holat. Yuqorida


Download 216.15 Kb.
bet12/17
Sana18.06.2023
Hajmi216.15 Kb.
#1591599
1   ...   9   10   11   12   13   14   15   16   17
Bog'liq
Abu rayxon beruniy nomidagi toshkent davlat texnika universiteti

Liniyaning boshlanishida quvvat va kuchlanish berilgan holat. Yuqorida


ko„rib o„tilgan holatdagi singari liniya toki
I12
ni liniyaning bo„ylama qismi

boshlanishidagi quvvat



S
(1)
12
va kuchlanish
U1 orqali ifodalasak, u holda ma‟lum

shakl almashtirishlardan so„ng liniyada kuchlanish pasayishining bo„ylama va ko„ndalang tashkil etuvchilari uchun liniya boshlanishidagi ma‟lumotlar bo„yicha ifodalarni hosil qilamiz:

(1) P(1) r
Q(1) x
; (3.30)

U12
12 12 12 12
U1


(1) P(1) x
Q(1) r
. (3.31)

U12
12 12 12 12
U1

Liniya oxiridagi kuchlanish:
U U  U ( 1 ) jU ( 1 ) . (3.32)
2 1 12 12

Yuqoridagilarga muvofiq liniya oxiridagi kuchlanish moduli va fazasi qo„yidagicha aniqlanadi:
U2  ; (3.33)


U (1)
2arctg 12 . (3.34)

U

12 

 1
U (1)



    1. ,b- rasmda tasvirlangan kuchlanishlar vektor diagrammasidan ko„rinadiki, kuchlanish pasayishining ko„ndalang tashkil etuvchisi U12 kichiklashgan sari kuchlanish isrofi kuchlanish pasayishining bo„ylama tashkil etuvchisiga yaqinlashib boradi. Shu sababli 110 kV va undan past kuchlanishli tarmoqlarni hisoblashda ushbu tashkil etuvchi etarlicha kichik bo„lganligi sababli liniya oxiridagi ma‟lumotlar bo„yicha hisoblashlarda

  
(2) P(2) r
Q(2) x
, (3.35)

U12
U12
12 12 12 12
U 2

liniya boshlanishidagi ma‟lumotlar bo„yicha hisoblashlarda esa

  


(1)  P(1) r
Q(1) x

U12

qabul qilinadi.


U12
12 12 12 12
U1
(3.36)
    1. Elektr tarmoqlarida kuchlanishni rostlash usullarini tadqiq qilish


Transformatorlarning transformatsiyalash koeffisientlarini o’zgartirib rostlash
Yuqorida ko‟rib o‟tilgan podstansiyalarda kuchlanishni rostlash usulining samaradorligi bilan sхemasi 3.3- rasmda keltirlgan elektr tarmog‟ida podstansiyaning pastki tomonida kuchlanishni rostlash misolida tanishamiz.

3.3-rasm


Kuchlanishni pasaytiruvchi podstansiyaning pastki tomonida Un hoh=10.5 kV kuchlanishni transformatorning transformatsiyalash koeffiseintini tanlash hisobiga rostlash talab etiladi.
Transformator kuchlanishni yuklama ostida rostlovchi YuOR ±9x1,78 tipidagi qurilma bilan jihozlangan.
Elektr tarmoqni almashtirish sxemasi tuzamiz va uning parametrlarini topamiz.
Liniya o‟tkazgichining markasi AC-185.
Uning solishtirma parametrlari: r0=0.17 Om/km, x0=0.409 Om/km/, b0=2.82 *10-6 Sm/km. Liniyaning uzunligi: l=50 km.
Liniya almashtirish sхemasining parametrlarini topamiz: rl=r0 *l=0.17*50=8.5 Om

N l
xl=x0*l=0.409*50=20.45 Om bl=b0*l=2.82*10-6*50=0.141*10-3 Sm Qs=U 2*b =1102*0.141=1.706 MVAr
Transformator markasi ТРДНЦ-40000/110
UYuK=115 kV UPK=10.5 kV Uk=10.5% i=0.5 ∆PS.I=120 kVt ∆PQT=265 kVt

R QT
*U 2
265 *1152



N
 2.19 , Om
X UK
%*U 2
10.5 *1152

 34.72 Om




N

N

S

N
T 2 402
T 100S
100 * 40

ST
 
S.I
 0.12 , MVt
QST
I S .I %* SN
100
0.5 * 40 0.2
100
MVar,

bu yerdagi PQT –qisqa tutashish isrofi, MVt
Uk % - qisqa tutashuv kuchlanishi, % UN
PS.I -salt ishlash isrofi, MVt IS.I % - salt ishlash toki, % IN
Elektr tarmoqning almashtirish sхemasini chizamiz (3.4-rasm)

3.4-rasm


Elektr tarmog‟ining holatini hisoblaymiz.

РT
Р2Q2

U
T T RT

N
352 152
1102
 2.19  0.262 MVt

QT
Р2Q2

U
T T XT

N
352 152
1102
34.72  4.16

MVAr


∆S=0.262+j4.16 MVA
S1 SYu ST (35 j15) (0,262 j4.16) 35.262 j19.16 MVA
S2 S1  Spul  (35.262  j19.16)  (0.12  j0,2)  35.382  j19.36 MVA
Liniyaning oxirida hosil bo‟lgan zaryad quvvatini hisobga olamiz:

S3 S2

  • QS

2


 (35.382 

j19.36)  j 1.706  35.382 


2
j18.507
MVA

Liniyadagi quvvat isrofi:

Р2Q2

U

2
РL 3 3RL
N
35.3822 18.5072
1102
8.5  1.12

MVt



QL
Р2Q2

U

2

L
3 3 X
N
35.3822 18.5072
1102
 20.45  2.69

MVAr


S4 S3  SL  (35.382  j18.507)  (1.12  j2.69)  36.502  j21.197
MVA

Liniyaning boshida generatsiya qilinayotgan quvvatni hisobga olamiz:



S5 S4

  • QS

2
 (36.502  j21.197)  j 1.706  36.502  j20.344
2

MVA


Kuchlanish yo‟qotilishini aniqlash Liniyadagi kuchlanish yo‟qolishi:

U12
Р4 RL Q4 ХL
UN
36.502 8.5 21.197 20.45 6.76 kV
110

2- tugundagi keltirilgan kuchlanish:
U2 U1 U12 110 6.76 103.24 kV
Transformatordagi kuchlanish yo‟qolishi:



U 23
Р1 RT Q1 ХT
U 2
35.262  2.19  19.16  34.72 7.2 kV
103.24

Podstansiyaning PK tomonidagi kuchlanish:
U3 U2 U23 103.24 7.2 95.04 kV
Shohobcha kuchlanishi:

Ushoh
U3 U PK
10.5
95.04 10.5 95.04 kV
10.5

Shohobchaning standart kuchlanishini tanlaymiz

Ust  96.55 kV
Podstansiyaning PK tomonidagi hohlangan kuchlanish:



UN .hoh
U 3
KT
95.64 10.5  10.5
96.55

kV.


Shunday qilib ushbu holatda podstansiyaning paski tomonida kuchlanishning talab etilgan qiymati 10,5 kV transformator transformatsiyalash koeffitsienti Kt=96,55/10,5 bo‟lganda ta‟minlanadi.


Tarmoqning reaktiv qarshiligini kompensasiyalab rostlash


Kuchlanishni elektr tarmoqning reaktiv qarshiligi kompensatsiyalab rostlash usulining samaradorligi bilan sхemasi 3.5- rasmda keltirilgan elektr tarmog‟ining oхirgi punktida 110 kV kuchlanishni ta‟minlash masalasida tanishib o‟tamiz.

3.5- rasm


Elektr tarmoqni almashtirish sxemasi tuzamiz va uning parametrlarini topamiz.
Liniya markasi AC-240 r0=0.13 Om/km x0=0.401 Om/km b0=2.85 *10-6 Sm/km l=40 km
RL1=r0 *l=0.13*40=5.2 Om XL1=x0*l=0.401*40=16.04 Om bL1=b0*l=2.85*10-6*40=0.114*10-3 Sm

Elektr tarmoqning almashtirish sхemasi 3.6- rasmda keltirilgan.


3.6- rasm.


Elektr tarmoqning holatini hisoblaymiz:


  1. N L1
    liniyaning zaryad quvvati: Qs1=U 2*b =1102*0.114=1.38 MVAr


  2. N L2
    liniyaning zaryad quvvati: Qs2=U 2*b =1102*0.0.0705=0.854 MVAr 2-Liniyaning oxirida hosil bo‟lgan zaryad quvvatini hisobga olamiz:

S4 S3

  • QS 2

2


 (15 

j7)  j 0.854  15  2


j6.573
MVA

Liniyadagi quvvat isrofi:

Р2Q2

U

2
РL2 4 4 RL2
N
152  6.5732
1102

 4.25  0.094


MVt



Р2Q2

U

2
QL2 4 4 XL2
N
152  6.5732
1102
10.225  0.23

MVAr


S5 S4  SL2  (15  j6.573)  (0.094  j0.23)  15.094  j6.803
MVA

Liniyaning boshida generatsiya qilinayotgan quvvatni hisobga olamiz:



S6 S5

  • QS 2

2
 (15.094  j6.803)  j 0.854  15.094  j6.376
2

MVA


S7 S6 S2  (15.094  j6.376)  (20  j8)  35.094  j14.376
MVA

1-Liniyaning oxirida hosil bo‟lgan zaryad quvvatini hisobga olamiz:



S8 S7

  • QS1

Download 216.15 Kb.

Do'stlaringiz bilan baham:
1   ...   9   10   11   12   13   14   15   16   17




Ma'lumotlar bazasi mualliflik huquqi bilan himoyalangan ©fayllar.org 2024
ma'muriyatiga murojaat qiling