Fozilova Sadoqat Ibrohim qizi Kimyodan masalalar yechish fanidan Mustaqil ta`limi

16-masala. 0,6 mol massasi 12 gr bo`lgan modda Mr ni toping?
0,6 mol--------12 gr
1mol ----------x=20 gr
17-masala. 0,5 mol massasi 24 gr bo`lgan moddani toping?
Mr=24/0,5=48 gr
Javob: O₃
18-masala. 0,5 mol massasi 9 gr bo`lgan moddani toping va tarkibini foizlarda aniqlang
Mr=9/0,5=18 gr H<sub>2</sub>O
ω=(2/18)*100%=11,11%
ω=(16/18)*100%=88,88%
19-masala. 2 mol massasi 80 gr bo`lgan moddani toping va tarkibini foizlarda aniqlang
Mr=80gr/2mol=40 gr MgO
ω=(24/40)*100%=60%
ω=(16/40)*100%=40%
20-masala. 1,5 mol massasi 96 gr bo`lgan moddani toping va tarkibini foizlarda aniqlang
Mr=96gr/1,5mol=64 gr SO<sub>2</sub>
ω=(32/64)*100%=50%
ω=(32/64)*100%=50%
21-masala. 2 mol massasi 196 gr bo`lgan moddani toping va tarkibini foizlarda aniqlang
2mol----------196gr
1mol-----------x=98gr H₂SO₄
ω=(2/98)*100%=2,04%
ω=(32/98)*100%=32,6%
ω=(64/98)*100%=65,3%
22-masala. 3 mol massasi 96 gr bo`lgan moddani toping?
3mol----------96 gr
1mol-----------x=32gr O<sub>2</sub>
23-masala. 0,5 mol massasi 32 gr bo`lgan moddani toping?
0,5mol---------32 gr
1mol-----------x=64 gr Cu
24-masala. 12 mol massasi 24 gr bo`lgan moddani toping?
12mol-----------24gr
1mol--------------x=2 gr H<sub>2</sub>
25-masala. 0,5 mol massasi 31,5 gr bo`lgan moddani toping?
0,5mol--------------31,5 gr
1mol--------------x=63 gr HNO₃