Ifodalarni ayniy almashtirish Maple muhitida funksiyalar va ular bilan amallar


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6-таксимот

> s:=solve(sqrt(x+3)

Agar siz tengsizlik yechimini (a, b) turdagi intervalli to’plamlar ko’rinishida emas , a<x, x< b turdagi izlanayotgan o’zgaruvchini chegaralanganlik ko’rinishida olmoqchi bo’lsangiz, u holda tengsizlik yechiladigan o’zgaruvchi figurali qavsda ko’rsatilishi lozim.



Masalan: > solve(1-1/2*ln(x)>2,{x});

Tengsizliklar sistemasini yechish. solve buyrug’i yordamida tengsiz-liklar sistemasini ham yechish mumkin. Masalan:

> solve({x+y>=2,x-2*y<=1,x-y>=0,x-2*y>=1},{x,y});

Qator yig’indisi va ko’paytmasini hisoblash

Chekli va cheksiz yig’indi ni to’g’ridan-to’g’ri bajarish buyrug’i sum va bajarish bekor qilingan buyrug’i Sum orqali belgilanadi. Bu buyruqlarning parametrlari bir xil: Sum(t, n=a..b); va sum(t, n=a..b); bu yerda t – yig’indining indeksiga bog’liq bo’lgan ifoda, a..b – esa yig’indini n=a dan n=b gacha bajarilishini ko’rsatuvchi yig’indi indeksining chegarasi.

> sum('k^2', 'k'=0..4);

> sum('k^2', 'k'=0..n);

> sum('k^2', 'k');

> sum('a[k]*x^k','k'=0..4);

> sum('a[k]*x^k','k'=0..n);

> Sum('k/(k+1)','k'=0..n) = sum('k/(k+1)', 'k'=0..n);

> sum('k/(k+1)', 'k');

  • sum('k*a^k', 'k');

  • Agar cheksiz qator yig’indisini hisoblash talab etilgan bo’lsa yuqori chegara sifatida infinity kiritiladi.

ko’paytma ham xuddi shunday bevosita bajarish buyrug’i product(P(n),n=a..b) va bajarilmaydigan buyrug’I Product P(n),n=a..b) yordamida belgilanadi

> product( k^2, k=1..4 );

> product( k^2, k=1..n );

> product( k^2, k );

> product( a[k], k=0..4 );

> product( a[k], k=0..n );

> Product( n+k, k=0..m ) = product( n+k, k=0..m );

> product( k, k=RootOf(x^3-2) );


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