Matematika 106/4


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Bog'liq
2004 variant


4)
5)
A) 2;4;5 B) 1;2;3 C) 2;3;4 D) 2;3;5 E) 1;3;5

  • To’g’ri burchakli uchburchakning balandligi gipotenuzani 98 va 2 ga teng kesmalarga ajratadi. Shu balandlikni toping.
    A) B) 14 C) D) E) 28

  • Quyidagi tasdiqlarning qaysilari to’g’ri?
    1) tomonlari va bo’lgan uchburchakka ichki chizilgan aylananing radiusi formula bilan hisoblanadi;
    2) radiusi ga, markaziy burchagi ga teng doiraviy sektorning yuzi formula bilan hisoblanadi;
    3) tomonlari va ga, ular orasidagi burchaklaridan biri ga teng bo’lgan paralellogrammning yuzi formula bilan hisoblanadi;
    4) diagonallari va ga, ular orasidagi burchagi ga teng ixtiyoriy qavariq to’rtburchakning yuzi formula bilan hisoblanadi;
    5) o’xshash figuralar yuzlarining nisbati ularning mos chiziqli o’lchovlarining nisbatiga teng;
    A) 1;2;4 B) 3;4;5 C) 2;3;5 D) 2;3;4 E) 1;3;4

  • Tekistlikka og’ma va perpendikulyar tushirilgan. Og’ma va tekistlik orasidagi burchak
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