Matematika o‘qitish metodikasi fanidan testlar. #Matеmatika so‘zining lug‘aviy ma’nоsi qanday-?

#2^x x² – 2  x² + 2 – 2^x = 0 tenglamaning ildizlari ko‘paytmasini toping.
+-1
-1
-2
--2

#Tenglamaning ildizlari yig’indisini toping: 9  16^x – 7  12^x – 16  9^x = 0

+2
--2
-3
--1

#Tenglamaning ildizlari ko‘paytmasini toping:

+-4
-2
-4
--2

#Sistema ildizlarini ifodalovchi nuqtalar orasidagi masofani toping:

+
-
-
-4


#а ni b orqali iodalang: 5^a = 3, 75^b = 81
+
-
-
-


#3^-x = 4 + x – x² tenglamani nechta yechimi bor?
+2
-1
-3
-4


#2^x = x³ tenglama nechta haqiqiy ildizga ega?
+2
-1
-2
-3

#Tengsizlikni eng katta butun yechimini toping:

+1
-2
--2
-4

#Funksiyaning aniqlanish sohasini toping:

y= log₃(x(x – 3)) – log₃x.
+(-; -1)
-(-; 0)
-(-; -2)
-(1; + )

#Hisoblang:

+14
-16
-7
-32

# Hisoblang:

+-27
-27
--8
-16


#log₄39,2 ni а va b orqali ifodalang : log₇2 = a, log₂10 = b
+
-
-
-

# tenglamaning ildizlari ko‘paytmasini toping.

+1
-9
-3
-2

# tenglamaning eng kichik butun yechimini toping.

+-2
--1
--3
-2

#Hisoblang: cos⁸165⁰ – cos⁸165⁰

+
-
-
-

#Hisoblang: tg (arctg 2 – arcos ).

+19/22
-1/2
-2/13
-18/22

#Hisoblang: sin (2 arctg 3) – cos (2 arctg 2)

+1,2
-1,4
--0,8
-0,8

# tenglamaning [0; 4 ] kesmada nechta ildizi bor.

+4
-6
-8
-2

#Tenglamani yeching: log_{sin x} cos x = 1

+/4 + 2 n, nZ
-- /4 +  n, n Z
-/4 + n, n Z
-/4

#Tengsizlikni [0;  ] oraliqdagi barcha yechimlarini aniqlang:

+[0;  /4] U[3/2; ]
-[/4;/2]U[3/2;2]
-[0;/4]U[3/4;2]
-[0;  /2] U [3/2; 2]

#Agar bo’lsa, x + y ni toping.

+2
-1
--1
--2

#Agar 5  x  y  z  z  t  320 bo’lsa, x/y + z/t ifodaning eng kichik qiymatini toping.

+0,25
-0,5
-0,6
-1,6

#Tengsizlikni yeching: x² – 7x + 12 < |x – 4|

+(2; 4)
-
-(3; 4)
-(2; 3)

#Agar bo’lsa, ni hisoblang.

+2/3
--2/3
-3
-3/2

# tengsizlikni nechta butun yechimi bor?

+6
-5
-3
-4

#O‘suvchi geometrik progressiyaning dastlabki uchta hadining yig‘indisi 24 ga teng. Shu progressiyaning ikkinchi hadini toping.

+8
-10
-6
-7

#Hisoblang: 100² – 97² +96²– 93² + 92² – 89² + … + 4² – 1²

+7575
-5055
-6675
-6775

#Tenglamani yeching: 1 – 3x + 9x² – … – (3x)⁹ = 0

+1/3
--1/3
-1/5
-3/4

#Bir hil raqamlardan iborat ikki honali sonlar yig‘indisini toping.

+495
-505
-491
-550


#1; 3;7;15; 31;…;2ⁿ –1 ketma-ketlikning dastlabki n ta hadining yig‘indisini toping.
+2(2ⁿ – 1) – n
-4ⁿ + 3
-2ⁿ + n + 1
-2²ⁿ + 4n


#a ning qanday qiymatida cheksiz kamayuvchi geometrik progressiyaning yig‘indisi 8 ga teng bo‘ladi?
+2 (2 - )
-2 +
-2 -
-

#Hisoblang:

+
-
-
-3

#Agar bo’lsa, x ni toping.

+17
-–  /6 +  K, K  Z
- /3
--17


#, ,  o‘tkir burchaklar bo‘lib, tg  = 1/2, tg  = 1/5, tg  = 7/9 bo‘lsa,  ni  va  lar orqali ifodalang.
+ =  + 
- = 2 + 
- =  + 2
- =  - 

#Hisoblang: cos 36⁰  cos 72⁰

+1/4
-1/2
-1/8
-1/12

#Soddalashtiring: sin⁶x + cos⁶x +(3 /4) sin²2

+1
--1
-sin²
-cos²


# ifodaning eng katta qiymatini toping.
+1/4
-1
-1/2
-2

#Hisoblang:

+1/4
-1
-1/2
-2

#Agar sin  = 1/3 bo’lsa, cos ( /4 – ) sin (3 /4 – ) ni hisoblang.

+ /4
- /2
-5/6
-3/4

#Soddalashtiring:

+– ctg²
-ctg²
-1
-tg²

#Agar tg  = 1/ 2 bo’lsa, sin (2  +  /4) ni hisoblang.

+-4/5
-4/5
-1/2
--1/2

#Hisoblang: sin 20⁰ sin 40⁰ sin 80⁰

+
-
-
-


#sin 16⁰ ni cos 37⁰ = a orqali ifodalang.
+2a² – 1
-a² – 1
-a –1
-1 – a²


#m ning lar ko‘rsatilgan tartibda arifmetik progressiya tashkil qiladigan qiymatlari yig‘indisni toping.
+12
-13
-8
-15

#Agar a = 2⁵ + 2^-5 va b = 2⁵ – 2^-5 bo’lsa, a² – b² ni toping?

+4
-2
-1/2
-1/4

#Hisoblang:

+4
-3
-5
-6

#Soddalashtiring:

+3 - 1
-2 + 2
-3 - 2
-3 + 2


#a = 5,2 da ifodani qiymatini hisoblang.
+-1,5
-2,5
-1,5
-2,4

#Soddalashtiring:

+2
-1
-3
-4

#Soddalashtiring:

+a – 1
-a² – 1
-a – 2
-

#Agar bo’lsa, ni hisoblang.

+2
--2
-1/2
--1/2


#a ning qanday qiymatlarida (a² + 2)x = a (x – 7) + 2 tenglamaning ildizlari cheksiz ko‘p bo‘ladi?
+
-
--
-- ;

# sistemasidan x ni toping.

+80/79
-3/7
-7/13
-79/80


#k ning qanday qiymatlarida tenglamalar sistemasi cheksiz ko‘p yechimga ega bo‘ladi?
+2
--1
--2
-1

#Ushbu (x² – x – 1) (x² – x – 7)  – 5 tengsizlikni eng katta va eng kichik butun ildizlari ayirmasini toping.

+5
-4
-3
-2

#Agar 9  x  y  z  t  81 bo’lsa, x/y + z/t ifodaning eng kichik qiymatini toping?

+2/3
-3/2
-1/5
-1/3

#Tenglamaning ildizlari yig’indisini toping: |x + 1| = 2 |x – 2|

+2
-3
-4
-1

#Agar bo’lsa, ni hisoblang.

+1/3
-2/3
--2/3
--1/3


#a soni b² – 3 bilan to‘g‘ri proporsional. b =5 bo‘lganda a = 88 bo‘lsa, b = -3 bo‘lganda a soni nechaga teng bo‘ladi?
+24
-6
-18
-12

# tengsizlikning butun yechimlari sonini toping.

+4
-3
-2
-6

#Funksiyaning aniqlanish sohasini toping:

+(-1; 1) U {2}
-(-1; 1)
-(-1; 2)
-(-; -1) U {2}


#m ning qanday qiymatlarida 4x² – ( m – 3)x – 9 = 0 tenglama turli ishorali ildizlarga ega bo’ladi?
+
-1,5
--1,6
--

#Hisoblang:

+416/515
-415/515
-69/103
-67/103

#Agar vektorlar uchun shart bajarilsa, х ni toping.

+0
-1
--1
-1,5

#Uchburchakning uchlari A(3; -2; 1), B (3; 0; 2) , C(1; 2; 5) nuqtalarda joylashgan. Shu uchburchakning BD medianasi va AC asosi orasidagi burchakni toping.

+45⁰
-30⁰
-60⁰
-arccos 1 /3

# vektor (1; 2; 2) vektorga kollinear hamda bu vektorlarning skalyar ko‘paytmasi 36 ga teng. vektorning uzunligini toping.

+12
-3
-4
-6

#Berilgan nuqtadan tekislikka uzunliklari 13 va 37 sm bo‘lgan ikkita og‘ma o‘tkazilgan. Og‘malarning tekislikdagi proyejsiyalari nisbati 1 : 7 kabi bo‘lsa, tekislikdan berilgan nuqtagacha bo‘lgan masofani toping.

+12
-11,5
-11
-19


#AB kesma  tekislikni O nuqtada kesib o‘tadi. Agar AO : OB = 3 : 2 bo‘lib, B nuqtadan x tekislikkacha bo`lgan masofa 8 ga teng bo`lsa, A nuqtadan  tekislikkacha bo`lgan masofani aniqlang.
+12
-11
-10
-9

# ifoda ma’noga ega bo‘lmaydigan (a;b) sonlar juftligini toping.

+(1; )
-(3;-1)
-(-3;1)
-( ;1)

# tenglamaning ildizi bo‘lsa, ifodaning qiymatini toping.

+50
-10
-5
-35