19.Rombning birburchagi 150о, balandligi esa 3,5 sm. Rombning perimetrini toping.
20.To’g’ri to’rtburchak diagonallari hosil qilgan burchaklardan biri 120оga, kichik tomoni esa 9 sm gateng. To’g’ri to’rtburchak diagonalini toping.
21.Uchburchakning o’rta chizig’iuningasosidan 3, 6 sm kichik. Uchburchakningo’rtachizig’ini toping.
22.Trapetsiyaningasoslaridanbiri 25 dm, o’rtachizig’iesa 30 dm. Trapetsiyaningikkinchiasosiuzunligini toping.
23. ABCD parallelogrammda AC = 10 sm, BD = 8 sm, BOC uchburchakning perimetri 16 sm, bunda O – AC va BD diagonallar kesishgan nuqta. AD tomon uzunligini toping.
24. ABC to’g’ri burchakli uchburchakda AB gipotenuza, AM va BN bissektrisalar. Agar AB = 16 va AM2 + BN2 = 320 bo’lsa, MN ning uzunligini toping.
25. Tomoni 5 sm va diagonallaridan biri 6 sm ga teng bo’lgan rombning o’tmas burchagidan tushirilgan balandlik uni uchburchak va to’rtburchakka ajratadi. Hosil bo’lgan shu to’rtburchakning perimetrini toping.
Для специализированных школ
Тесты 8 класс
3- вариант.
1. Упростите : ![](data:image/png;base64,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)
A) –5 B) 13 C) D)
2. Найдите наибольшее значение выражения ,
если 4 ≤ x ≤ 10 и 5 ≤ y ≤ 11.
A) 8,5 B) 7 C) 5,5 D) 3,863
3. Вычислите x3y + xy3 , если x – y = 3 и xy = 6.
A) 126 B) 128 C) 108 D) 72
4. Упростите выражение: ![](data:image/png;base64,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)
А) –1 С) 2 С) 2 D)
5. Найдите сумму корней уравнения .
6. Найдите отношение большего корня уравнения
к меньшему.
7. Найдите координаты точки пересечения графика
с осью абсцисс.
Do'stlaringiz bilan baham: |