Mavzu: Moddalarning berilgan massasi ulushi, foiz ulushi aniqlash, murakkab moddalarning formulalarini keltirib chiqarishga oid masalalar

11-masala. Absolut massasi 1,59*10²³ bo`lgan element atomini toping
1,59*10<sup>23</sup>*6,02*10<sup>23</sup>=96 Mo
12-masala. III valentli nomalum element hosil qilgan oksidning ekvivalent massasi=12,667. Elementni toping
E<sub>2</sub>O<sub>3</sub>
Mr=12,667*2*3=76
76-48=28
28/2=14 N azot
13-masala. ω O<sub>2</sub> =96% bo`lgan vodorod va kisloroddan iborat gazlar aralashmasining o`rtacha Mr=?
100--------100%
X=96---------96%
96/32=48
4/32=2,125
100/5=25
14-masala. ω H<sub>2</sub>=20% bo`lgan vodorod va kisloroddan iborat gazlar aralashmasining o`rtacha Mr=?
100-------100%
X=20--------20%
X=80----------80%
20/2=10
80/32=2,5
100/12,5=8
15-masala. ω H<sub>2</sub>=60% bo`lgan vodorod va kisloroddan iborat gazlar aralashmasining o`rtacha Mr=?
100------------100%
X=60-----------60%
X=40-----------40%
60/2=30
40/32=1,25 1mol-------100%
X=0,6 mol-----60%
X=0,4mol-------40%
0,6*2=1,2
0,4*32=12,8
12,8+1,2=14/1=14
16-masala. 0,6 mol massasi 12 gr bo`lgan modda Mr ni toping?
0,6 mol--------12 gr
1mol ----------x=20 gr
17-masala. 0,5 mol massasi 24 gr bo`lgan moddani toping?
Mr=24/0,5=48 gr
Javob: O<sub>3</sub>
18-masala. 0,5 mol massasi 9 gr bo`lgan moddani toping va tarkibini foizlarda aniqlang
Mr=9/0,5=18 gr H₂O
ω=(2/18)*100%=11,11%
ω=(16/18)*100%=88,88%
19-masala. 2 mol massasi 80 gr bo`lgan moddani toping va tarkibini foizlarda aniqlang
Mr=80gr/2mol=40 gr MgO
ω=(24/40)*100%=60%
ω=(16/40)*100%=40%
20-masala. 1,5 mol massasi 96 gr bo`lgan moddani toping va tarkibini foizlarda aniqlang
Mr=96gr/1,5mol=64 gr SO₂
ω=(32/64)*100%=50%
ω=(32/64)*100%=50%
21-masala. 2 mol massasi 196 gr bo`lgan moddani toping va tarkibini foizlarda aniqlang
2mol----------196gr
1mol-----------x=98gr H₂SO₄
ω=(2/98)*100%=2,04%
ω=(32/98)*100%=32,6%
ω=(64/98)*100%=65,3%