Yig‘indi va ayirma formulalari:
kosinuslar har doim "juft bo'lib ketadi". Ikkita kosinus - "bulochka" qo'shib, biz bir juft kosinus - "koloboks" ni olamiz. Va ayirish, biz, albatta, koloboklarni olmaymiz. Biz bir nechta sinuslarni olamiz. Oldinda hali minus.
Sinuslar - "aralash" :
Yig’indilarga doir misollar 1-Misol. Yechish: cos15=cos(45-30) ekanligidan va cosinus uchun Cos(45-30)=cos45 = + Javob: + 2-Misol. Cos()Cos() - sin ()sin () ni hisoblang 2-Misol. Cos()Cos() - sin ()sin () ni hisoblang Yechish: Cosinus uchun cos( formuladan foydalansak Cos()Cos() - sin ()sin () Cos() cos Javob: -1 3-Misol. Sin( ni hisoblang 3-Misol. Sin( ni hisoblang Yechish: Sin( sin cos + cos - sin cos bo’ladi Javob: sin cos 4-Misol. Sin5x cos3x – cos5x sin3x ni hisoblang 4-Misol. Sin5x cos3x – cos5x sin3x ni hisoblang Yechish: Sinus uchun sin (=sin sin Formuladan foydalansak Sin5x cos3x – cos5x sin3x Sin(5x-3x) Sin2x Javob: 2x 5-Misol. Agar cost=- va bo’lsa, sin( +t) ni hisoblang 5-Misol. Agar cost=- va bo’lsa, sin( +t) ni hisoblang Yechish: Birinchi navbatda burchakning qaysi chorakka tegishli ekanligini aniqlab olamiz, cost=- dan sint= kelib chiqadi. sin ( +t) =sin ()+ cos () sint (- )+ = - Javob: -
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